1 / 8

Combustion Fundamentals: Mass Diffusion and Droplet Evaporation

This article discusses the governing equations and solution for the 1-D Stefan problem in combustion, with a focus on mass diffusion and droplet evaporation. It explores the effects of concentrations at the interface and top of the tube, as well as the liquid-vapor interface boundary conditions. Latent heat of vaporization and the D2 law are also examined. Examples and calculations for benzene and n-dodecane droplet evaporation are included.

ahopson
Download Presentation

Combustion Fundamentals: Mass Diffusion and Droplet Evaporation

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. MAE 5310: COMBUSTION FUNDAMENTALS Mass Diffusion and Droplet Evaporation November 28, 2007 Mechanical and Aerospace Engineering Department Florida Institute of Technology D. R. Kirk

  2. 1-D STEFAN PROBLEM Governing equations Solution • To see effects of concentrations at interface and at top of tube, let mass fraction of A in freestream be zero, while arbitrarily varying YA,i, interface mass fraction, from zero to unity • In terms of an experiment, this would be like blowing dry N2 across top of tube and interface mass fraction is controlled by partial pressure of liquid, which in turn is varied by changing temperature • At small values of YA,i, dimensionless mass flux is basically proportional to YA,i, but for values greater than about 0.5, mass flux increases very rapidly

  3. LIQUID VAPOR INTERFACE BOUNDARY CONDITIONS Key question: How can we assess the value of YA,i? • Equilibrium exists between liquid and vapor phase of species A • Partial pressure of species A on gas side of interface must equal saturation pressure associated with temperature of liquid: PA,i = Psat(Tliq,i) • Partial pressure, PA,i, can be related to mole and mass fraction of species A • Molecular weight of mixture also depends on cA,i, and hence on psat • Analysis has transformed problem of finding vapor mass fraction at interface to finding temperature at the interface • Must be found by writing an energy balance for liquid and gas phases and solving them with appropriate boundary conditions, including that at interface • In cross liquid-vapor boundary, temperature continuity is maintained: • Tliq,i(x = 0-) = Tvap,i(x = 0+) = T(0) • Energy is conserved at interface: • Heat is transferred from gas to liquid with some of energy going into heating liquid and remainder causing phase change

  4. LATENT HEAT OF VAPORIZATION, hfg • In many combustion systems a liquid ↔ vapor phase change is important • Example: Liquid fuel droplet must first vaporize before it can burn • Example: If cooled sufficiently, water vapor can condense from combustion products • Latent Heat of Vaporization (also called enthalpy of valorization), hfg: Heat required in a constant P process to completely vaporize a unit mass of liquid at a given T • hfg(T,P) ≡ hvapor(T,P)-hliquid(T,P) • T and P correspond to saturation conditions • Latent heat of vaporization is frequently used with Clausius-Clapeyron Equation to estimate Psat variation with T • Assumptions: • Specific volume of liquid phase is negligible compared to vapor • Vapor behaves as an ideal gas • If hfg is constant integrate to find Psat,2 if Tsat,1 Tsat2, and Psat1 are known • We will do this for droplet evaporation and combustion, e.x. D2 law

  5. SIMPLE EXAMPLE • Liquid benzene (C6H6) at 298 K is contained in a 1 cm diameter glass tube and maintained at a level 10 cm below the top of the tube, which is open to the atmosphere • Determine mass evaporation rate (kg/s) of benzene • How long does it take to evaporate 1 cm3 of benzene? • Compare evaporation rate of benzene with water • Given data: • Tboil = 353 K at 1 atm • hfg = 393 kJ/kg at Tboil • MWC6H6 = 78 kg/kmol • Density of liquid benzene = 879 kg/m3 • DC6H6-Air = 0.99x10-5 m2/s at 298 K • DH20-Air = 2.6x10-5 m2/s at 298 K

  6. DROPLET EVAPORATION • Evaporation of a single liquid droplet in a quiescent atmosphere is the Stephan problem for spherical symmetry • Key question: How long does it take for a liquid drop to evaporate? • Assumptions for simplified treatment • Evaporation process is quasi-steady • Droplet temperature is uniform and below the boiling point of the liquid • In many actual problems transient heating of liquid does not affect droplet lifetime substantially • Mass fraction of vapor at droplet surface is determined by liquid-vapor equilibrium at the droplet temperature • All thermodynamic properties are constant • In reality properties vary greatly in gas phase • Constant properties allow a closed form solution

  7. D2 LAW RESULTS

  8. SIMPLE EXAMPLE: DROPLET EVAPORATION • In mass-diffusion-controlled evaporation of a fuel droplet, the droplet surface temperature is an important parameter • Estimate the droplet lifetime, td, of a 100 mm diameter n-dodecane droplet evaporating in dry nitrogen at 1 atmosphere if the droplet temperature is 10 K below the n-dodecane boiling point. • Repeat the calculation for a temperature 20 K below the boiling point and compare • Assume that in both cases the mean gas density of nitrogen is that of nitrogen at 800 K and use the same temperature to estimate the fuel vapor diffusivity • Given properties • Density of n-dodecane is 749 kg/m3 • Tboil = 489.5 K • hfg = 256 kJ/kg • MW = 170 • Dn-dodecane-N2 = 8.1x10-6 m2/s at 400 K and 1 atmosphere

More Related