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Class 3: Estimating Scoring Rules for Sequence Alignment

Class 3: Estimating Scoring Rules for Sequence Alignment. Reminder. Last class we discussed dynamic programming algorithms for global alignment local alignment

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Class 3: Estimating Scoring Rules for Sequence Alignment

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  1. Class 3: Estimating Scoring Rules for Sequence Alignment .

  2. Reminder • Last class we discussed dynamic programming algorithms for • global alignment • local alignment • All of these assumed a pre-specified scoring rule (substitution matrix):that determines the quality of perfect matches, substitutions and indels, independently of neighboring positions.

  3. A Probabilistic Model • But how do we derive a “good” substitution matrix? • It should “encourage” pairs, that are probable to change in close sequences, and “punish” others. • Lets examine a general probabilistic approach, guided by evolutionary intuitions. • Assume that we consider only two options: M: the sequences are evolutionary related R: the sequences are unrelated

  4. Unrelated Sequences • Our model of 2 unrelated sequences s, t is simple: • For each position i, both s[i], t[i] are sampled independently from some “background” distributionq(·) over the alphabet . • Let q(a) be the probability of seeing letter a in any position. • Then the likelihood of s, t (probability of seeing s, t),giventhey are unrelated is:

  5. Related Sequences • Now lets assume that each pair of aligned positions (s[i],t[i]) evolved from a common ancestor =>s[i],t[i] are dependent ! • We assume s[i],t[i] are sampled from some distributionp(·,·)of letters pairs. • Let p(a,b) be a probability that some ancestral letter evolved into this particular pair of letters • Then the likelihood of s, t,given they are related is:

  6. Decision Problem • Given two sequences s[1..n] and t[1..n] decide whether they were sampled from M or from R • This is an instance of a decision problem that is quite frequent in statistics: hypothesis testing • We want to construct a procedure Decide(s,t) = D(s,t) that returns either M or R • Intuitively, we want to compare the likelihoods of the data in both models…

  7. Types of Error • Our procedure can make two types of errors: I. s and t are sampled from R, but D(s,t) = M II. s and t are sampled from M, but D(s,t) = R • Define the following error probabilities: • We want to find a procedure D(s,t) that minimizes both types of errors

  8. Neyman-Pearson Lemma • Suppose that D* is such that for some k • If any other D is such that (D)  (D*), then (D)  (D*) -->D* is optimal • k might refer to the weights we wish to give to both types of errors, and on relative abundance of M comparing to R

  9. Likelihood Ratio for Alignment • The likelihood ratio is a quantitative measure of two sequences being derived from a common origin, compared to random. • Lets see, that it is a natural score for their alignment ! • Plugging in the model, we have that:

  10. Likelihood Ratio for Alignment • Taking logarithm of both sides, we get • We can see that the (log-)likelihood score decomposes to sum of single position scores, each dependent only on the two aligned letters !

  11. Probabilistic Interpretation of Scoring Rule • Therefore, if we take our substitution matrix be: then the score of an alignment is the log-ratio between the two models likelihoods, which is nice. • Score > 0M is more “probable” (k=1) • Score < 0R is more “probable”

  12. Modeling Assumptions • It is important to note that this interpretation depends on our modeling assumption of the two hypotheses!! • For example, if we assume that the letter in each position depends on the letter in the preceding position, then the likelihood ration will have a different form.

  13. Constructing Scoring Rules The formula suggests how to construct a scoring rule: • Estimatep(·,·) and q(·) from the data • Compute (a,b) based on p(·,·) and q(·)

  14. Estimating Probabilities • Suppose we are given a long string s[1..n] of letters from  • We want to estimate the distribution q(·) that “generated” the sequence • How should we go about this? • We build on the theory of parameter estimation in statistics

  15. Statistical Parameter Fitting • Consider instances x[1], x[2], …, x[M] such that • The set of values that x can take is known • Each is sampled from the same (unknown) distribution of a known family (multinomial, Gaussian, Poisson, etc.) • Each is sampled independently of the rest • The task is to find a parameters set  defining the most likely distribution P(x|), from which the instances could be sampled, I.e. • The parameters  depend on the given family of probability distributions.

  16. Example: Binomial Experiment • When tossed, it can land in one of two positions: Head or Tail • We denote by  the (unknown) probability P(H). Estimation task: • Given a sequence of toss samples x[1], x[2], …, x[M] we want to estimate the probabilities P(H)=  and P(T) = 1 -  Head Tail

  17. Why Learning is Possible? • Suppose we perform M independent flips of the thumbtack • The number of head we see is a binomial distribution • and thus This suggests, that we can estimate  by

  18. Expected Behavior ( = 0.5) • From most large datasets, we get a good approximation to  • How do we derive such estimators in a principled way? M = 10 M = 100 M = 1000 Probability (rescaled) over datasets of i.i.d. samples 0 0.2 0.4 0.6 0.8 1

  19. L( :D)  0 0.2 0.4 0.6 0.8 1 The Likelihood Function • How good is a particular ?It depends on how likely it is to generate the observed data • The likelihood for the sequence H,T, T, H, H is

  20. Maximum Likelihood Estimation • MLE Principle: Learn parameters that maximize the likelihood function • This is one of the most commonly used estimators in statistics • Intuitively appealing

  21. Computing the Likelihood Functions • To compute the likelihood in the thumbtack example we only require NH and NT (the number of heads and the number of tails) • NH and NT are sufficient statistics for the binomial distribution

  22. Datasets Statistics Sufficient Statistics • A sufficient statistic is a function of the data that summarizes the relevant information for the likelihood • Formally, s(D) is a sufficient statistics if for any two datasets D and D’ • s(D) = s(D’ )  L( |D) = L( |D’)

  23. Example: (NH,NT) = (3,2) MLE estimate is3/5 = 0.6 L(:D) 0 0.2 0.4 0.6 0.8 1 Example: MLE in Binomial Data • Applying the MLE principle we get (after differentiating) (Which coincides with what we would expect)

  24. From Binomial to Multinomial • Suppose X can have the values 1,2,…,K • We want to learn the parameters 1, 2. …, K Sufficient statistics: • N1, N2, …, NK - the number of times each outcome is observed Likelihood function: MLE (differentiation with Lagrange multipliers):

  25. At last: Estimating q(·) • Suppose we are given a long string s[1..n] of letters from  • s can be the concatenation of all sequences in our database • We want to estimate the distribution q(·) Likelihood function: MLE parameters: Number of times a appears in s

  26. Estimating p(·,·) Intuition: • Find pair of presumably relatedaligned sequences s[1..n], t[1..n] • Estimate probability of pairs in the sequence: • Again, s and t can be the concatenation of many aligned pairs from the database Number of times a is aligned with b in (s,t)

  27. Estimating p(·,·) Problems: • How do we find pairs of presumably related aligned sequences? • Can we ensure that the two sequences are indeed based on a common ancestor? • How far back should this ancestor be? • earlier divergence  low sequence similarity • later divergence  high sequence similarity • The substitution score of each 2 letters should depend on the evolutionary distance of the compared sequences !

  28. A T T C T A C C G G Let Evolution In • Again, we need to make some assumptions: • Each position changes independently of the rest • The probability of mutations is the same in each positions • Evolution does not “remember” Time t+ t+2 t+3 t+4 t

  29. Model of Evolution • How do we model such a process? • The process (for each position independently) is called a Markov Chain • A chain is defined by the transition probability P(Xt+=b|Xt=a) - the probability that the next state is b given that the current state is a • We often describe these probabilities by a matrix:T[]ab =P(Xt+=b|Xt=a)

  30. Two-Step Changes • Based on T[], we can compute the probabilities of changes over two time periods • Thus T[2] = T[]T[] • By induction: T[k] = T[] k

  31. Longer Term Changes Idea: • Estimate T[] from some closely related sequences set S • Use T[] to compute T[k] • Derive substitution probability after time k: • Note, that the score depends on evolutionary distance, as requested

  32. Estimating PAM1 • Collect counts Nabof aligned pairs (a,b) in similar sequences in S • Sources include phylogenetic trees and close related sequences (at least 85% positions have exact match) • Normalize counts to get transition matrix T[] , such that average number of changes is 1% • that is, • this is called 1 point accepted mutation (PAM1) – an evolutionary time unit !

  33. Using PAM • The matrix PAM-k is defined to be the score based on Tk • Historically researchers use PAM250 • Longer than 100 ! • Original PAM matrices were based on small number of proteins • Later versions of PAM use more examples • Used to be the most popular scoring rule

  34. Problems with PAM • PAM extrapolates statistics collected from closely related sequences onto distant ones. • But “short-time” substitutions behave differently than “long-time” substitutions: • short-time substitutions are dominated by a single nucleotide changes that led to different translation (like L->I) • long-time substitutions dominated do not exhibit such behavior, are much more random. • Therefore, statistics would be different for different stages in evolution.

  35. BLOSUM (blocks substitution) matrix • Source: aligned ungapped regions of protein families • These are assumed to have a common ancestor • Procedure: • Group together all sequences in a family with more than e.g. 62% identical residues • Count number of substitutions within the same family but across different groups • Estimate frequencies of each pair of letters • The resulting matrix is called BLOSUM62

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