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Common Ion Effect

Common Ion Effect. Buffers. Common Ion Effect . Sometimes the equilibrium solutions have 2 ions in common For example if I mixed HF & NaF The main reaction is HF  H + + F -. Common Ion Effect . Which way will the reaction shift if NaF is added? What effect will this have on pH?.

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Common Ion Effect

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  1. Common Ion Effect Buffers

  2. Common Ion Effect • Sometimes the equilibrium solutions have 2 ions in common • For example if I mixed HF & NaF • The main reaction is HF  H+ + F-

  3. Common Ion Effect • Which way will the reaction shift if NaF is added? • What effect will this have on pH?

  4. Example • What is the pH of a 0.10M solution of HC2H3O2 (Ka = 1.8 x10-5)

  5. Example HC2H3O2 H+ + C2H3O2- Ka = 1.8 x 10-5

  6. Example • A mixture contains 0.10M HC2H3O2 (Ka = 1.8 x10-5) & 0.10 M NaC2H3O2. Calculate the pH.

  7. Example HC2H3O2 H+ + C2H3O2- Ka = 1.8 x 10-5

  8. What are buffers? • Buffers resist changes in pH • They must have 2 parts… • Weak acid & a conjugate base OR • Weak base & a conjugate acid • The concentrations of the 2 MUST be with in a factor of 10!!!

  9. Buffers

  10. Example • What is the pH of a solution containing 50. mL of 0.50M NaC2H3O2 & 25 mL of 0.25M HC2H3O2. (Ka = 1.8 x10-5).

  11. Example HC2H3O2 H+ + C2H3O2- Ka = 1.8 x 10-5

  12. Henderson Hasselbach Equation • Really easy equation to use ONLY with buffer solutions!!! • pH = pKa + log [B]/[A]

  13. The last example using HH • pH = pKa + log [B]/[A]

  14. Example (ICE TABLE) • What is the pH of a solution containing 25 mL of 0.150MHClO & 32mL of 0.45M KClO. Ka = 3.5x10-8

  15. Example (ICE TABLE) HClO H+ + ClO- Ka = 3.5x10-8

  16. Example (HH) • pH = pKa + log [B]/[A]

  17. Example (ICE TABLE) • What is the pH of a solution containing 25 mL of 0.50M CH3NH3NO3 is mixed with 75 mL of 0.30 M CH3NH2 (Kb CH3NH2 = 4.38 x10-4)

  18. Example (ICE TABLE) CH3NH2 + H2O  CH3NH3+ + OH- Ka = 4.38x10-4

  19. Example • Calculate the mass of NaF that must be added to 1000.0 ml of 0.50M HF to form a solution with a pH of 4.00. Ka = 7.2x10-4

  20. Example (ICE TABLE) HF  H + + F- Ka = 7.2x10-4

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