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Equation of Tangent line

Equation of Tangent line. circle. x 2 + y 2 = 100. tangent line. 4x – 3y = 50. point of tangency. (8,6). m t =. m r =. The slope of the radius is the negative reciprocal to the slope of the tangent line . The circle above is defined by the equation: x 2 + y 2 = 100 .

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Equation of Tangent line

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  1. Equation of Tangent line

  2. circle x2 + y2 = 100 tangent line 4x – 3y = 50 point of tangency (8,6) mt = mr = The slope of theradius is the negative reciprocal to the slope of the tangent line. The circle above is defined by the equation: x2 + y2 = 100. A tangent line (4x – 3y = 50) intersects the circle at a point of tangency: (8,6). The tangent line is perpendicular to the radius of the circle. The circle above is defined by the equation: x2 + y2 = 100. A tangent line (4x – 3y = 50) intersects the circle at a point of tangency: (8,6). The tangent line is perpendicular to the radius of the circle. The circle above is defined by the equation: x2 + y2 = 100. A tangent line (4x – 3y = 50) intersects the circle at a point of tangency: (8,6). The tangent line is perpendicular to the radius of the circle. The circle above is defined by the equation: x2 + y2 = 100. A tangent line (4x – 3y = 50) intersects the circle at a point of tangency: (8,6). The tangent line is perpendicular to the radius of the circle.

  3. C(-1,2) P(2,-1) P(2,-1) T(0,-3) mr = When a tangent and a radius intersect at the point of tangency, they are always perpendicular to each other. It then follows that their slopes are always negative reciprocals of each other.

  4. R(-2,1) Find the slope of the line tangent to the circle x2 + y2 = 5 and passing through the point R(-2,1).

  5. Step 1: Find the centre and the radius. x2 + y2 + 10x – 24y = 0 Step 3: Find the slope of the tangent. Step 2: Find the slope of the radius. Step 4: Find the equation of the tangent. Find the equation of the tangent to the circle x2 + y2 + 10x – 24y = 0 and passing through the point T(0,0). (x2 + 10x + 25) + (y2 – 24y + 144) = 0 + 25 + 144 (x + 5)2 + (y– 12)2 = 169 Centre: (-5,12) r = 13 12(y – 0) = 5(x – 0) 12y = 5x 5x – 12y = 0

  6. Find the equation of the tangent to the circle x2 + y2 – 6y - 16 = 0 and passing through the point T(3,7). Step 1: Find the centre and the radius. x2 + y2 – 6y - 16 = 0 x2 + (y2 – 6y + 9) = 16 + 9 x2 + (y– 3)2 = 25 Centre: (0,3) r = 5 4(y – 7) = -3(x – 3) 4y - 28 = -3x + 9 3x + 4y = 9 + 28 3x + 4y = 37

  7. finito

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