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Sometimes you have a formula and you need to solve for some variable other than

Sometimes you have a formula and you need to solve for some variable other than the "standard" one. Example: Perimeter of a square P=4s It may be that you need to solve this equation for s , so you can plug in a perimeter and figure out the side length. Solving Literal Equations.

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Sometimes you have a formula and you need to solve for some variable other than

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  1. Sometimes you have a formula and you need to solve for some variable other than the "standard" one. Example: Perimeter of a square P=4s It may be that you need to solve this equation for s, so you can plug in a perimeter and figure out the side length.

  2. Solving Literal Equations

  3. Solving a Literal Equation

  4. This process of solving a formula for a given variable is called "solving literal equations".

  5. One of the dictionary definitions of "literal" is "related to or being comprised of letters“. Variables are sometimes referred to as literals.

  6. So "solving literal equations" may just be another way of saying "taking an equation with lots of variables, and solving for one variable in particular.”

  7. To solve literal equations, you do what you've done all along to solve equations, except that, due to all the variables, you won't necessarily be able to simplify your answers as much as you're used to doing.

  8. Here's how "solving literal equations" works: Suppose you wanted to take the formula for the perimeter of a square and solve it for ‘s’ (or the side length) instead of using it to solve for perimeter. P=4s How can you get the ‘s’ on a side by itself?

  9. P=4s Just as when you were solving linear equations, you want to isolate the variable. So, what do you have to do to get rid of the ‘4’?

  10. P=4s That’s right, you have to divide by ‘4’. You also have to remember to divide both sides by 4.

  11. This new formula allows us to use the perimeter formula to find the length of the sides of a square if we know the perimeter.

  12. Let’s look at another example: Solve for d. 2Q-c = d Multiply both sides by 2. Subtract ‘c’ from each side.

  13. As you can see, we sometimes must do more that one step in order to isolate the targeted variable. You just need to follow the same steps that you would use to solve any other ‘Multi-Step Equation’.

  14. Your Turn: Solve 5 – b = 2t for t. 5 – b = 2t Locate t in the equation. Since t is multiplied by 2, divide both sides by 2 to undo the multiplication.

  15. Solve for V Your Turn: Locate V in the equation. Since m is divided by V, multiply both sides by V to undo the division. VD = m Since V is multiplied by D, divide both sides by D to undo the multiplication.

  16. Definition • Formula – is an equation that states a rule for a relationship among quantities. • A formula is a type of literal equation. • In the formula d = rt, d is isolated. You can "rearrange" a formula to isolate any variable by using inverse operations. • Examples: • Circumference: C = 2πr • Area of Triangle: A = 1/2bh

  17. A = bh Since bh is multiplied by , divide both sides by to undo the multiplication. Example: Solving Formulas The formula for the area of a triangle is A = bh, where b is the length of the base, and is the height. Solve for h. Locate h in the equation. 2A = bh Since h is multiplied by b, divide both sides by b to undo the multiplication.

  18. Remember! Dividing by a fraction is the same as multiplying by the reciprocal.

  19. ms = w – 10e –w –w ms – w = –10e Example: Solving Formulas The formula for a person’s typing speed is ,where s is speed in words per minute, w is number of words typed, e is number of errors, and m is number of minutes typing. Solve for e. Locate e in the equation. Since w–10e is divided by m, multiply both sides by m to undo the division. Since w is added to –10e, subtract w from both sides to undo the addition.

  20. Example: Continued Since e is multiplied by –10, divide both sides by –10 to undo the multiplication.

  21. f = i – gt + gt +gt Your Turn: The formula for an object’s final velocity is f = i – gt, where i is the object’s initial velocity, g is acceleration due to gravity, and t is time. Solve for i. f = i – gt Locate i in the equation. Since gt is subtracted from i, add gt to both sides to undo the subtraction. f + gt = i

  22. Example: Application The formula C = d gives the circumference of a circle C in terms of diameter d. The circumference of a bowl is 18 inches. What is the bowl's diameter? Leave the symbol  in your answer. Locate d in the equation. Since d is multiplied by , divide both sides by  to undo the multiplication. Now use this formula and the information given in the problem.

  23. The bowl's diameter is inches. Example: Continued The formula C = d gives the circumference of a circle C in terms of diameter d. The circumference of a bowl is 18 inches. What is the bowl's diameter? Leave the symbol  in your answer. Now use this formula and the information given in the problem.

  24. Your Turn: Solve the formula d = rt for t. Find the time in hours that it would take Ernst Van Dyke to travel 26.2 miles if his average speed was 18 miles per hour. d = rt Locate t in the equation. Since t is multiplied by r, divide both sides by r to undo the multiplication. Now use this formula and the information given in the problem. Van Dyke’s time was about 1.46 hrs.

  25. Work these on your paper. 1. d = rt for ‘r’ 2. P = 2l+2w for ‘w’ 3. for ‘t’

  26. Check your answers. 1. d = rt for ‘r’ 2. P = 2l+2w for ‘w’ 3. for ‘t’

  27. Your Turn: More Practice Solve for the indicated variable. 1. 2. 3. 2x + 7y = 14 for y 4. for h P = R – C for C C = R – P for m m = x(k – 6) 5. for C C = Rt + S

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