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Wavelength & frequency relationship of an electromagnetic wave

It describes the wavelength and frequency relationship of an electromagnetic wave.

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Wavelength & frequency relationship of an electromagnetic wave

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  1. WAVELENGTH & FREQUENCY RELATIONSHIP BY JAYAM CHEMISTRY LEARNERS

  2. Wavelength of an electromagnetic wave 1. It is the distance between the identical points on adjoining waveforms. 2. We measure it differently for transverse and longitudinal waves. 3. The length between the two adjacent crests or troughs is wavelength in transverse waves. And in longitudinal waves, it is the calculation of the gap between the corresponding compressions or rarefactions. 4. The Greek letter Lambda (λ) designates it. 5. The nanometer is the most commonly used unit to express the wavelength of electromagnetic waves. 6. The instrument called "Wave meter" measures the wavelength of light radiations.

  3. Frequency of an electromagnetic wave 1. The frequency is the number of waves that pass through a given point in a unit time. Energy-Frequency relationship 2. The symbol γ denotes it. Its units are cycles per second or Hertz. 3. According to quantum theory, the energy of the photon varies directly with the frequency. 4. Hence, with an increase in frequency, the energy of the light radiation increases. And the less energetic light radiations have lower frequencies.

  4. Relationship between the wavelength and frequency of an electromagnetic wave: According to quantum theory, the product of wavelength and frequency is equal to the velocity of electromagnetic radiation in a vacuum. Velocity= wavelength X frequency Where, c= velocity of light radiation in vacuum and its value is 3X108 m/sec λ= wavelength of the light γ= frequency of the light radiation

  5. Why do shorter waves have higher frequencies 1. The wavelength of electromagnetic radiation varies inversely with its frequency. 2. Hence, the shorter waves have higher frequencies and vice versa. 3. When the wavelengths of the light radiations decrease, their frequencies increase. 4. So, gamma rays have high frequencies and shorter wavelengths in the electromagnetic spectrum.

  6. Numerical problem-1 Question: What happens to the wavelength of light when the frequency doubles? Answer: The frequency and wavelength of light radiations are inversely proportional to each other. The inversely proportional relationship between the two is below: Where, λ= wavelength of the light γ = frequency c = velocity of the light in vacuum and is a constant quantity

  7. Let us rewrite the above equation in terms of wavelength as below; According to the question, when the frequency of a wave doubles, the modified wavelength equation can be as below;

  8. By comparing the above two equations, we will get as shown below; It implies that when the frequency of a wave doubles, then its wavelength is reduced to one-half. Numerical problem-2 Question: How does the frequency of electromagnetic wave A compare to the frequency of that of electromagnetic wave B if the ratio of their wavelengths is 1:3?

  9. Let us consider the wavelength of electromagnetic wave A=x The wavelength of electromagnetic wave B= 3x We know that, the frequency and wavelength of the electromagnetic radiations are inversely proportional to each other. The inversely proportional relationship between the two is below: The frequency of the electromagnetic wave A after putting the wavelength value is;

  10. The frequency of the electromagnetic wave B after putting the wavelength value is; By comparing the frequencies of both the electromagnetic waves A & B we get;

  11. Hence, the ratio of frequencies of electromagnetic waves A & B is 3:1. Numerical problem-3 A transmitter emits electromagnetic radiation having a frequency of 1.368 kHz. Calculate its wavelength? The formula to calculate the wavelength of electromagnetic radiation is; Where, γ = frequency c= velocity of the light in vacuum and is a constant quantity

  12. Substituting the values of c and γ in the above equation, we get; 3 × 108?/? 1.368 × 103?−1 λ = 1 kHz= 103HZ = 103s-1 λ= 2.1929X105m

  13. Thank you For more information on this topic, kindly visit our blog article at; https://jayamchemistrylearners.blogspot.com/2022/04/bohr-sommerfeld-model-chemistrylearners.html Our blog discusses interesting topics of chemistry with regular new post updates. You can have a look at it and follow it. https://jayamchemistrylearners.blogspot.com/ You can send your valuable suggestions and any doubts regarding chemistry subject through these social media channels. Instagram : https://www.instagram.com/chemistrylearners/ Pinterest : https://in.pinterest.com/kameswariservices/_created/ Facebook https://www.facebook.com/jayamchemistrylearners

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