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Physics 101: Lecture 19 Elasticity and Oscillations II

Exam III. Physics 101: Lecture 19 Elasticity and Oscillations II. m. x. x=0. PE S. x. 0. Review Energy in SHM. A mass is attached to a spring and set to motion. The maximum displacement is x= A Energy = U + K = constant! = ½ k x 2 + ½ m v 2 At maximum displacement x= A , v = 0

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Physics 101: Lecture 19 Elasticity and Oscillations II

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  1. Exam III Physics 101: Lecture 19 Elasticity and OscillationsII

  2. m x x=0 PES x 0 Review Energy in SHM • A mass is attached to a spring and set to motion. The maximum displacement is x=A • Energy = U + K = constant! = ½ k x2 + ½ m v2 • At maximum displacement x=A, v = 0 Energy = ½ k A2 + 0 • At zero displacement x = 0 Energy = 0 + ½ mvm2 ½ k A2 = ½ m vm2 vm = sqrt(k/m) A • Analogy w/ marble in bowl 05

  3. Simple Harmonic Motion:Quick Review x(t) = [A]cos(t) v(t) = -[A]sin(t) a(t) = -[A2]cos(t) x(t) = [A]sin(t) v(t) = [A]cos(t) a(t) = -[A2]sin(t) OR Period = T (seconds per cycle) Frequency = f = 1/T (cycles per second) Angular frequency =  = 2f = 2/T xmax = A vmax = A amax = A2 19

  4. Period T of a Spring • Simple Harmonic Oscillator • w = 2 p f = 2 p / T • x(t) = [A] cos(wt) • v(t) = -[Aw] sin(wt) • a(t) = -[Aw2] cos(wt) • For a Spring F = -kx • amax = (k/m) A • Aw2 = (k/m) A w = sqrt(k/m) Demos: A,m,k dependence 23

  5. Question If the amplitude of the oscillation (same block and same spring) is doubled, how would the period of the oscillation change? (The period is the time it takes to make one complete oscillation) A. The period of the oscillation would double.B. The period of the oscillation would be halvedC. The period of the oscillation would stay the same x +2A t -2A 27

  6. Vertical Mass and Spring • If we include gravity, there are two forces acting on mass. With mass, new equilibrium position has spring stretched d • SF = kd – mg = 0 d = mg/k Let this point be y=0 • SF = k(d-y) – mg = -k y • Same as horizontal! SHO • New equilibrium position y=-d 31

  7. PE = 1/2k y2 PE = 1/2k y2 Vertical Spring Question If the springs were vertical, and stretched the same distance d from their equilibrium position and then released, which would have the maximum kinetic energy? 1) M 2) 2M 3) Same Y=0 Y=0 33

  8. Pendulum Motion • For small angles • T = mg • Tx = -mg (x/L) Note: F proportional to x! • S Fx = m ax -mg (x/L) = m ax ax = -(g/L) x • Recall for SHO a = -w2 x • w = sqrt(g/L) • T = 2 p sqrt(L/g) • Period does not depend on A, or m! L T m x mg 37

  9. Example: Clock • If we want to make a grandfather clock so that the pendulum makes one complete cycle each sec, how long should the pendulum be?

  10. Question 1 Suppose a grandfather clock (a simple pendulum) runs slow. In order to make it run on time you should: 1. Make the pendulum shorter 2. Make the pendulum longer 38

  11. Elevator ACT A pendulum is hanging vertically from the ceiling of an elevator. Initially the elevator is at rest and the period of the pendulum is T. Now the pendulum accelerates upward. The period of the pendulum will now be 1. greater than T 2. equal to T 3. less than T “Effective g” is larger when accelerating upward (you feel heavier) 44

  12. Question Imagine you have been kidnapped by space invaders and are being held prisoner in a room with no windows. All you have is a cheap digital wristwatch and a pair of shoes (including shoelaces of known length). Explain how you might figure out whether this room is on the earth or on the moon 50

  13. Summary • Simple Harmonic Motion • Occurs when have linear restoring force F= -kx • x(t) = [A] cos(wt) • v(t) = -[Aw] sin(wt) • a(t) = -[Aw2] cos(wt) • Springs • F = -kx • U = ½ k x2 • w = sqrt(k/m) • Pendulum (Small oscillations) • w = sqrt(L/g) 50

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