1 / 5

Properties of Real Numbers

3 4. – is between –1 and 0. Use a calculator to find that 7 2.65. Properties of Real Numbers. ALGEBRA 2 LESSON 1-1. 3 4. Graph the numbers – , 7 , and 3.6 on a number line. 1-1. 9 = 3, so – 9 = –3. –9 < – 9. Properties of Real Numbers.

dane-hodges
Download Presentation

Properties of Real Numbers

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 3 4 – is between –1 and 0. Use a calculator to find that 7 2.65. Properties of Real Numbers ALGEBRA 2 LESSON 1-1 3 4 Graph the numbers – , 7 , and 3.6 on a number line. 1-1

  2. 9 = 3, so – 9 = –3. –9 < – 9. Properties of Real Numbers ALGEBRA 2 LESSON 1-1 Compare –9 and – 9. Use the symbols < and >. Since –9 < –3, it follows that 1-1

  3. Opposite: –(–3 ) = 3 1 7 1 7 1 1 7 22 Reciprocal: = = – 1 7 22 7 –3 – 1 4 Reciprocal: Properties of Real Numbers ALGEBRA 2 LESSON 1-1 Find the opposite and the reciprocal of each number. 1 7 a. –3 b. 4 Opposite: –4 1-1

  4. Properties of Real Numbers ALGEBRA 2 LESSON 1-1 Which property is illustrated? a. (–7)(2 • 5) = (–7)(5 • 2) b. 3 • (8 + 0) = 3 • 8 The given equation is true because 2 • 5 = 5 • 2. The given equation is true because 8 + 0 = 8. So, the equation uses the Commutative Property of Multiplication. This is an instance of the Identity Property of Addition. 1-1

  5. 1 3 1 3 1 3 1 3 4 is 4 units from 0, so | 4 | = 4 . Properties of Real Numbers ALGEBRA 2 LESSON 1-1 1 3 Simplify | 4 |, |–9.2|, and |3 – 8|. –9.2 is 9.2 units from 0, so |–9.2| = 9.2. |3 – 8| = |–5| and –5 is 5 units from 0. So, |–5| = 5, and hence |3 – 8| = 5. 1-1

More Related