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Expected Value Reprise

Expected Value Reprise. CP Canoe Club Duck Derby Maximum of 2 000 tickets sold $5/ticket Prizes 12 VIP tickets to Cirque du Soleil ($2,000) 32gb BlackBerry Playbook ($600) $250 Should Mr. Lieff buy a ticket?. Expected Value Calculation. 2 000 tickets

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Expected Value Reprise

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  1. Expected Value Reprise • CP Canoe Club Duck Derby • Maximum of 2 000 tickets sold • $5/ticket • Prizes • 12 VIP tickets to Cirque du Soleil ($2,000) • 32gb BlackBerry Playbook ($600) • $250 • Should Mr. Lieff buy a ticket?

  2. Expected Value Calculation • 2 000 tickets • E(X) =1/2000 (2000) + 1/2000(600)+1/2000(250) • = 1.425 • Mr. Lieff receives a hot tip that only 1 500 tickets will be sold. • E(X) =1/1500 (2000) + 1/1500(600)+1/1500(250) • = 1.9

  3. Probability Distributions and Expected Value Chapter 5.1 – Probability Distributions and Predictions Learning goals: Calculate probabilities and expected value

  4. Probability Distributions of a Discrete Random Variable • a discrete random variable X is a variable that can take on only a finite set of values • for example, rolling a die can only produce numbers in the set {1,2,3,4,5,6} • rolling 2 dice can produce only numbers in the set {2,3,4,5,6,7,8,9,10,11,12} • choosing a card from a standard deck (ignoring suit) can produce only the cards in the set {A,2,3,4,5,6,7,8,9,10,J,Q,K}

  5. Probability Distribution • the probability distribution of a random variable X, is a function which provides the probability of each possible value of X • this function may be represented as a table of values, a graph or a mathematical expression • for example, rolling a die:

  6. Probability Distribution for 2 Dice

  7. What would a probability distribution graph for three dice look like? • We will try it! Using three dice, figure out how many outcomes there are • Then find out how many possible ways there are to create each of the possible outcomes • Fill in a table like the one below • Now you can make the graph

  8. Probability Distribution for 3 Dice

  9. So what does an experimental distribution look like? • A simulated dice throw was done a million times using a computer program and generated the following data • What is/are the most common outcome(s)? • Does this make sense?

  10. Back to 2 Dice • What is the expected value of throwing 2 dice? • How could this be calculated? • So the expected value of a discrete variable X is the sum of the values of X multiplied by their probabilities

  11. Example 1a: tossing 3 coins • What is the likelihood of at least 2 heads? • It must be the total probability of tossing 2 heads and tossing 3 heads • P(X = 2) + P(X = 3) = ⅜ + ⅛ = ½ • so the probability is 0.5

  12. Example 1b: tossing 3 coins • What is the expected number of heads? • It must be the sums of the values of x multiplied by the probabilities of x • 0P(X = 0) + 1P(X = 1) + 2P(X = 2) + 3P(X = 3) • = 0(⅛) + 1(⅜) + 2(⅜) + 3(⅛) = 1½ • So the expected number of heads is 1.5

  13. Example 2a: Selecting a Committee of three people from a group of 4 men and 3 women • What is the probability of having at least one woman on the committee? • There are C(7,3) or 35 possible teams • C(4,3) = 4 have no women • C(4,2) x C(3,1) = 6 x 3 = 18 have one woman • C(4,1) x C(3,2) = 4 x 3 = 12 have 2 women • C(3,3) = 1 has 3 women

  14. Example 2a cont’d: selecting a committee • What is the likelihood of at least one woman? • It must be the total probability of all the cases with at least one woman • P(X = 1) + P(X = 2) + P(X = 3) • = 18/35 + 12/35 + 1/35 = 31/35

  15. Example 2b: selecting a committee • What is the expected number of women? • 0P(X = 0) + 1P(X = 1) + 2P(X = 2) + 3P(X = 3) • = 0(4/35) + 1(18/35) + 2(12/35) + 3(1/35) • = 1.3 (approximately) • MSIP / Homework: p. 277 #1-5, 9, 12, 13

  16. MSIP / Homework • p. 277 #1-5, 9, 12, 13

  17. Pascal’s Triangle and the Binomial Theorem Chapter 5.2 – Probability Distributions and Predictions Learning goal: Generate Pascal’s Triangle and use it to solve counting problems pascals_triangle.mp3

  18. How many routes are there to the top right-hand corner? • Move up 4 spaces and over 5 spaces • Same as rearranging the letters NNNNEEEEE • Calculated by • 9! • 4!5! • C(9,4) or C(9,5) • = 126 ways

  19. Permutation AND Combination? • As a permutation: • There are 9 moves  9! • However, 4 are identical N moves and 5 are identical E moves • Divide by 4! due to identical arrangements of Ns • Divide by 5! due to identical arrangements of Es •  9! ÷ 4!5! = 126 • As a combination: • There are 9 moves required _ _ _ _ _ _ _ _ _ • Choose 4 to be Ns, the rest are Es  C(9, 4) = 126 • Choose 5 to be Es, the rest are Ns  C(9, 5) = 126

  20. Pascal’s Triangle • outer values: always 1 • inner values: add the two values diagonally above • 1 • 1 1 • 1 2 1 • 1 3 3 1 • 1 4 6 4 1 • 1 5 10 10 5 1

  21. Pascal’s Triangle • sum of each row is a power of 2 • 1 = 20 • 2 = 21 • 4 = 22 • 8 = 23 • 16 = 24 • 32 = 25 • 64 = 26 • 1 • 1 1 • 1 2 1 • 1 3 3 1 • 1 4 6 4 1 • 1 5 10 10 5 1 • 1 6 15 20 15 6 1

  22. Pascal’s Triangle • Uses? • binomial theorem • combinations! • e.g. choose 2 items from 5 • go to the 5th row, the 2nd number = 10 (always start counting at 0) • modeling the electrons in each shell of an atom (google ‘Pascal’s Triangle electron’) • 1 • 1 1 • 1 2 1 • 1 3 3 1 • 1 4 6 4 1 • 1 5 10 10 5 1 • 1 6 15 20 15 6 1

  23. Pascal’s Triangle – Cool Stuff • each diagonal is summed below and to the left • called the “hockey stick” property • 1 • 1 1 • 1 2 1 • 1 3 3 1 • 1 4 6 4 1 • 1 5 10 10 5 1 • 1 6 15 20 15 6 1 • may be music hidden in it • pascals_triangle.mp3

  24. Music: Three Parts in D Alternating Octatonic • The piece of music has three parts: • 1) A treble part where the center numbers 1, 2 and 6 are the tonic D of the D alternating octatonic scale. The other vertical lines of numbers represent one scale step; a descending scale step to the left and an ascending scale step to the right. All ways of reaching all the numbers in the triangle are mapped to consecutive sixteenths, starting from the top and going down south west first to every new row, inwards. This part is repeated. • 2) The main treble part. It has the structure A1 B A2 B. It starts with the left side of the symmetric triangle, including the center (A1), the numbers are the number of scale steps to ascend (south east arrows) or descend (south west arrows). After an intermission (B) where this part doubles the first part, the right side is initiated (A2) and it is the mirror image of A1. • 3) A walking bass part (quarter notes), same as the first treble part but consecutive equal tones are tied. This part is repeated. • Playing time: 4' 47".

  25. Pascal’s Triangle – Cool Stuff • e.g., numbers divisible by 5 • similar patterns for other numbers • http://www.shodor.org/interactivate/activities/pascal1/

  26. Pascal’s Triangle can also be seen in terms of combinations • n = 0 • n = 1 • n = 2 • n = 3 • n = 4 • n = 5 • n = 6

  27. Pascal’s Triangle - Summary • symmetrical down the middle • outside number is always 1 • second diagonal values match the row numbers • sum of each row is a power of 2 • sum of nth row is 2n • Begin count at 0 • number inside a row is the sum of the two numbers above it

  28. How many paths are there from X to Y? As a checkerboard As a grid Y X

  29. Warm up How many ways are there to spell the word SNOWMAN?

  30. The Binomial Theorem • the term (a + b) can be expanded: • (a + b)0 = 1 • (a + b)1 = a + b • (a + b)2 = a2 + 2ab + b2 • (a + b)3 = a3 + 3a2b + 3ab2 + b3 • (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4 • Blaise Pascal (for whom the Pascal computer language is named) noted that there are patterns of expansion, and from this he developed what we now know as Pascal’s Triangle. He also invented the second mechanical calculator.

  31. So what does this have to do with the Binomial Theorem? • remember that the binomial expansion: • (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4 • and the triangle’s 4th row is 1 4 6 4 1 • Pascal’s Triangle allows you to determine the coefficients • The exponents on the variables form a predictable pattern • The exponents of each term sum to n

  32. The Binomial Theorem

  33. A Binomial Expansion • Expand (x + y)4

  34. Another Binomial Expansion • Expand (a – 4)5

  35. Some Binomial Examples • what is the 6th term in (a + b)9? • don’t forget that when you find the 6th term, r = 5 • what is the 11th term of (2x + 4)12

  36. Look at the triangle in a different way • r0 r1 r2 r3 r4 r5 • n = 0 1 • n = 1 1 1 • n = 2 1 2 1 • n = 3 1 3 3 1 • n = 4 1 4 6 4 1 • n = 5 1 5 10 10 5 1 • n = 6 1 6 15 20 15 6 1 • for a binomial expansion of (a + b)5, the term for r = 3 has a coefficient of 10

  37. And one more thing… • remember that for the inner numbers in the triangle, any number is the sum of the two numbers above it • for example 4 + 6 = 10 • this suggests the following: • which is an example of Pascal’s Identity

  38. For Example…

  39. How can this help us solve our original problem? • so by overlaying Pascal’s Triangle over the grid we can see that there are 126 ways to move from one corner to another

  40. How many routes pass through the green square? • to get to the green square, there are C(4,2) ways (6 ways) • to get to the end from the green square there are C(5,3) ways (10 ways) • in total there are 60 ways

  41. How many routes do not pass through the green square? • there are 60 ways that pass through the green square • there are C(9,5) or 126 ways in total • then there must be 126 – 60 = 66 paths that do not pass through the green square

  42. MSIP/ Homework • Read the examples on pages 281-287, in particular the example starting on the bottom of page 287 is important • Complete p. 289 #1, 2aceg, 3, 4, 5, 6, 8, 9, 11, 13

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