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The Superposition Principle

The Superposition Principle. 2 m. q 2 =4 m C. q 1 = 3 m C. What is the force acting on q 2 ?. q 3 = -4 m C. 25°. 25°. 4 m. q 1 =2 m C. q 2 =3 m C. What is the force acting on q 3 ?. r q1q3 = r q2q3 = 2m /cos 25° = 2.21 m. = -1.56 x 10 -2 N. = 6.71 x 10 -3 N.

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The Superposition Principle

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  1. The Superposition Principle

  2. 2 m q2 =4mC q1 = 3mC What is the force acting on q2?

  3. q3 = -4 mC 25° 25° 4 m q1 =2mC q2 =3mC What is the force acting on q3? rq1q3 = rq2q3 = 2m /cos 25° = 2.21 m = -1.56 x 10-2 N = 6.71 x 10-3 N

  4. Fy = -1.56 x 10-2 N Fx = 6.71 x 10-3 N q Magnitude of resultant vector: c2 = a2 + b2 = 1.70 x 10-2 N Direction of resultant vector: q = tan-1 (side opp/side adj) = 23.3° 270° + 23.3° = 293.3°

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