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What is the percent composition of carbon in C 14 H 18 N 2 O 5 ?

DO NOW ! On Notebook Paper…. What is the percent composition of carbon in C 14 H 18 N 2 O 5 ? What is the empirical formula for a compound that contains 42.05% nitrogen and 95.95% oxygen? What is the empirical formula for a compound that contains 13.5% Ca, 10.8% O, and 0.675% H?. Notes.

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What is the percent composition of carbon in C 14 H 18 N 2 O 5 ?

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  1. DO NOW! On Notebook Paper… • What is the percent composition of carbon in C14H18N2O5 ? • What is the empirical formula for a compound that contains 42.05% nitrogen and 95.95% oxygen? • What is the empirical formula for a compound that contains 13.5% Ca, 10.8% O, and 0.675% H?

  2. Notes Unit: Chemical Quantities Determining the Molecular Formula from the Empirical Formula

  3. After today, you will be able to… Calculate the empirical formulas for various compounds given their percent makeup

  4. Molecular Formula Determination from the Empirical Formula To determine molecular formulas from the empirical formula follow these steps: • First determine the empirical formula • Use the formula: • Multiply the subscripts in the empirical formula by this whole number to get the molecular formula Molar mass of molecular formula Molar mass of empirical formula

  5. 1 mol C 12.01gC 6.16 70.4gC 8.70gH 17.3gN Example: What is the molecular formula for a compound that is 74.0% C, 8.70% H, and 17.3% N and has a molar mass of 243.39g? Empirical: C5H7N x = = 5 5C=12.01(5) = 60.05 1 mol H 1.01gH 8.61 7H=1.01(7) = 7.07 = x 1.23 1.23 1.23 = 7 1N=14.01(1) = +14.01 1 mol N 14.01gN 1.23 81.07 1 = x = = 3 x C5H7N C15H21N3 243.39 81.07

  6. 1 mol Na 22.990gNa 1.49 34.31gNa 17.93gC 47.76gO WS #5:What is the molecular formula for a compound that is 34.31% sodium, 17.93% carbon, 47.76% oxygen and has a molar mass of 134.00g? Empirical: NaCO2 x = = 1 1Na = 22.990(1) = 22.99 1 mol C 12.011gC 1.49 1C =12.011 (1) = 12.011 = x 1.49 1.49 1.49 = 1 2O =15.999(2) = +31.998 1 mol O 15.999gO 2.99 66.999 2 = x = = 2 x NaCO2 Na2C2O4 134.00 66.999

  7. HOMEWORK: Time to Practice!Complete WS

  8. DOLWrite the molecular formulas of the following compounds: • A compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole. • The compound benzamide has the following percent composition. What is the empirical formula? C = 69.40 % H= 5.825 % O = 13.21 % N= 11.57 % • A component of protein called serine has an approximate molar mass of 100 g/mole. If the percent composition is as follows, what is the empirical and molecular formula of serine? C = 34.95 % H= 6.844 % O = 46.56 % N= 13.59 %

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