1 / 10

Unit: Gas Laws

Day 3 – Notes. Unit: Gas Laws. Gay-Lussac’s and Combined Gas Laws. After today you will be able to…. Explain the effect on gas properties using Gay-Lussac’s Law and the Combined Gas Law Calculate an unknown pressure, temperature, or volume by solving algebraically.

erling
Download Presentation

Unit: Gas Laws

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Day 3 – Notes Unit: Gas Laws Gay-Lussac’s and Combined Gas Laws

  2. After today you will be able to… • Explain the effect on gas properties using Gay-Lussac’s Law and the Combined Gas Law • Calculate an unknown pressure, temperature, or volume by solving algebraically

  3. Gay-Lussac’s Law: Pressure and Temperature Joseph Gay-Lussac discovered the relationship between temperature and pressure. • His name is on the gas law that describes this relationship.

  4. “For a given volume of a gas, as the temperature of an enclosed gas increases, the pressure of a gas is directly proportional.”

  5. Gay-Lussac’s Law: Pressure and Temperature We can simplify this relationship by the formula: Where, P1, P2 = pressure in any unit (atm, kPa, or mmHg), BUT they must match! T1, T2 = temperature is always in Kelvin! (Recall, just add 273 + °C) P1P2 T1 T2 =

  6. Gay-Lussac’s Law: Example A gas has a pressure of 103kPa at 25°C. What will the pressure be when the temperature reaches 928°C? P1= T1= P2= T2= 103kPa P1P2 T1 T2 = 25°C +273= 298K ? • 928°C+273= 1201K • (P2) (103kPa) = (1201K) (298K) 420kPa • P2 =

  7. The Combined Gas Law RB + JC + JG-L = BFFs! The combined gas law is a single expression that combines Boyle’s, Charles’s, and Gay-Lussac’s Laws. • This gas law describes the relationship between temperature, pressure, and volume of a gas. • It allows you to do calculations where only the amount of gas is constant.

  8. The Combined Gas Law Helpful hint: You are able to get which law you need by covering the variable that is not mentioned in the problem! There is no need to memorize 4 individual laws, just memorize the Combined Gas Law and you can derive all of the others! If there is no mention of pressure in the problem, cover P up and you are left with the relationship between T and V. (aka Charles’s Law!) For example, if there is no mention of temperature in the problem, cover T up and you are left with the relationship between P and V. (aka Boyle’s Law!) If there is no mention of volume in the problem, cover V up and you are left with the relationship between T and P. (aka Gay-Lussac’s Law!) P1V1P2V2 T1T2 =

  9. The Combined Gas Law A gas occupies 3.78L at 529mmHg and 17.2°C. At what pressure would the volume of the gas be 4.54L if the temperature is increased to 34.8°C? P1= V1= T1= P2= V2= T2= P1V1P2V2 T1 T2 = 529mmHg 3.78L • 17.2°C + 273= 290.2K • (P2) (4.54L) (3.78L) (529mmHg) • ? = (307.8K) (290.2K) 4.54L 467mmHg • P2 = • 34.8°C + 273= 307.8K

  10. Questions?Complete WS 3

More Related