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5 Ω

5 Ω. 4 Ω. 9 Ω. 9 Ω. 9 Ω. 5 Ω. 8 Ω. 3 Ω. 10.24 Ω. 4.24 Ω. 6 Ω. 6 Ω. 6 Ω. 9 Ω. 9 Ω. 11. Find the current through the 3 Ω resistor if the entire combination is connected across a 24V source of emf . . 1. First simplify the circuit. 24V. 2. Identify the unknown: I 3 =?.

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5 Ω

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  1. 5Ω • 4Ω • 9Ω • 9Ω • 9Ω • 5Ω • 8Ω • 3Ω • 10.24Ω • 4.24Ω • 6Ω • 6Ω • 6Ω • 9Ω • 9Ω 11 Find the current through the 3Ωresistor if the entire combination is connected across a 24V source of emf. 1. First simplify the circuit 24V 2. Identify the unknown: I3=? 3. Work backwards using what you know about series / parallel • I3=I5 Current is same in series 24V • I3= I8b/c they are equivalent 9.94 V • V4.24= V8= V9 b/c they are parallel 9.94 V • I6= I10.24 Current is same in series 24V 4. Get crackin’ find I10.24 first 2.34 A I10.24= VT/R10.24 = 24/10.24 = 2.34 A 9.94 V 5. To find V8you’ll need to find V4.24 24V 2.34 A V4.24 = I4.24R4.24 = (2.34 A)(4.24) =9.94V

  2. 5Ω • 4Ω • 9Ω • 9Ω • 9Ω • 5Ω • 8Ω • 3Ω • 10.24Ω • 4.24Ω • 6Ω • 6Ω • 6Ω • 9Ω • 9Ω 11 Find the current through the 3Ωresistor if the entire combination is connected across a 24V source of emf. Work backwards using what you know about series / parallel 24V • I3=I5 Current is same in series • I3= I8 b/c they are equivalent • V4.24= V8= V9 b/c they are parallel • I6= I10.24 Current is same in series 6. Now find I8 24V I8 = V8/R8 = 9.94/8 = 1.24 A 2.34 A 9.94 V 7. Realize that I8= I3 Feel victorious! 24V I3 = 1.24 A 2.34 A 9.94 V 24V 2.34 A

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