1 / 13

ECEN3713 Network Analysis Lecture #13 21 February 2006 Dr. George Scheets

ECEN3713 Network Analysis Lecture #13 21 February 2006 Dr. George Scheets. Exam 1 Results: Hi = 95, Low = 25, Ave. = 60.14, StanDev = 21.18 A > 90, B > 77, C > 55, D > 40 Read Chapter 13.8, 14.1 - 14.3 Problems: 13.14, 13.38, 13.84, 14.1 Thursday's Quiz

Download Presentation

ECEN3713 Network Analysis Lecture #13 21 February 2006 Dr. George Scheets

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. ECEN3713 Network AnalysisLecture #13 21 February 2006Dr. George Scheets Exam 1 Results: Hi = 95, Low = 25, Ave. = 60.14, StanDev = 21.18A > 90, B > 77, C > 55, D > 40 • Read Chapter 13.8, 14.1 - 14.3 • Problems: 13.14, 13.38, 13.84, 14.1 • Thursday's Quiz • 1st or 2nd Order Circuits with initial conditions Thursday's AssignmentProblems: 14.2 - 14.5

  2. ECEN3713 Network AnalysisLecture #15 28 February 2006Dr. George Scheets Quiz 4 Results: Hi = 10, Low = 2, Ave. = 6.62, StanDev = 2.40 • Read Chapter 14.4 • Problems: 14.7, 14.9, 14.10, 14.13 • Thursday's Quiz • Chapter 14.1 – 14.4 Thursday's AssignmentProblems: 14.14 - 14.16, 14.19

  3. 10.2 Im x t -1 Re x V(s) = 10s/(s2+2s+25) v(t) = 10.2e-tcos(4.899t + .0641π) Stability Issues: Underdamped Location of poles on Real axis sets decay rate. Location of poles on Imagninary axis sets oscillation rate.

  4. v(t) 100 Im t .001 x x -5000 Re V(s) = (100s + 106)/(s + 5000)2 v(t) = 500,000te-5000t + 100e-5000t Stability Issues: Critically damped Location of poles on Real axis sets decay rate.

  5. v(t) .5 t .002 V(s) = 105/(s2 + 2*105s + 108) v(t) = .5025(e-500t - e-199,500t) Stability Issues: Overdamped No complex poles = no oscillation. Location of poles on real axis sets decay rate. Im x x Re -199,500 -500

  6. 1.5 0 -1.5 1.0 0 1.5 0 -1.5 1.0 0 Generating a Square Wave... 1 vp 5 Hz 1/3 vp 15 Hz

  7. Generating a Square Wave... 1.5 5 Hz+ 15 Hz 0 -1.5 1.0 0 1.5 1/5 vp 25 Hz 0 -1.5 1.0 0

  8. Generating a Square Wave... 5 Hz+ 15 Hz + 25 Hz 1.5 0 -1.5 1.0 0 1.5 1/7 vp 35 Hz 0 -1.5 1.0 0

  9. Generating a Square Wave... 5 Hz+ 15 Hz + 25 Hz + 35 Hz 1.5 0 -1.5 1.0 0 cos2*pi*5t - (1/3)cos2*pi*15t + (1/5)cos2*pi*25t - (1/7)cos2*pi*35t) 5 cycle per second square wave generated using 4 sinusoids

  10. Generating a Square Wave... 1.5 0 -1.5 1.0 0 5 cycle per second square wave generated using 50 sinusoids.

  11. Generating a Square Wave... 1.5 0 -1.5 1.0 0 5 cycle per second square wave generated using 100 sinusoids.

  12. X(f) = x(t) e-j2πft dt Fourier -∞ Transforms ∞ Laplace X(s) = x(t) e-st dt 0-

More Related