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Physics 207, Lecture 3

Physics 207, Lecture 3. Today (Finish Ch. 2 & start Ch. 3) Understand acceleration in systems with 1-dimensional motion and non-zero acceleration (usually constant) Solve problems with zero and constant acceleration (including free-fall and motion on an incline)

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Physics 207, Lecture 3

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  1. Physics 207, Lecture 3 • Today (Finish Ch. 2 & start Ch. 3) • Understand acceleration in systems with 1-dimensional motion and non-zero acceleration (usually constant) • Solve problems with zero and constant acceleration (including free-fall and motion on an incline) • Use Cartesian and polar coordinate systems • Perform vector algebra Reading Assignment: For Wednesday: Read Chapter 3 (carefully) through 4.4

  2. x displacement vectors “2D” Position, Displacement y time (sec) 1 2 3 4 5 6 position -2,2 -1,2 0,2 1,2 2,2 3,2 (x,y meters) position vectors origin

  3. x displacement vectors 12 23 34 45 56 Position, Displacement, Velocity y time (sec) 1 2 3 4 5 6 velocity vectors Velocity always has same magnitude & length  CONSTANT

  4. v0 v1 v1 v1 v3 v5 v2 v4 v0 Acceleration • Particle motion often involves non-zero acceleration • The magnitude of the velocity vector may change • The direction of the velocity vector may change (true even if the magnitude remains constant) • Both may change simultaneously • E.g., a “particle” with smoothly decreasing speed

  5. Average & Instantaneous Acceleration • Average acceleration • The instantaneous acceleration is the limit of the average acceleration as ∆v/∆t approaches zero • Note: Position, velocity & acceleration are all vectors, they cannot be added directly to one another (different dimensional units)

  6. x t vx t Position, velocity & acceleration for motion along a line • If the positionx is known as a function of time, then we can find both the instantaneous velocityvxand instantaneous accelerationax as a function of time! ax t

  7. v1 v0 v3 v5 v2 v4 a a a a a a t 0 Going the other way…. • Particle motion with constant acceleration • The magnitude of the velocity vector changes • A particle with smoothly decreasing speed: v a Dt vf = vi + a Dt = vi + a (tf - ti ) t 0 tf ti a Dt = area under curve = Dv (an integral)

  8. So if constant acceleration we can integrate to get explicit v and a x x0 t vx v0 t ax t

  9. Rearranging terms gives two other relationships • If constant acceleration then we also get: Slope of x(t) curve

  10. vx t An example problem • A particle moves to the right first for 2 seconds at 1 m/s and then 4 seconds at 2 m/s. • What was the average velocity? • Two legs with constant velocity but …. • We must find the displacement (x2 –x0) • And x1 = x0 + v0 (t1-t0) x2 = x1 + v1 (t2-t1) • Displacement is (x2 - x1) + (x1 – x0) = v1 (t2-t1) + v0 (t1-t0) • x2 –x0 = 1 m/s (2 s) + 2 m/s (4 s) = 10 m in 6 seconds or 5/3 m/s Slope of x(t) curve

  11. A particle starting at rest & moving along a line with constant acceleration has a displacement whose magnitude is proportional to t2 1. This can be tested2. This is a potentially useful result

  12. Speed can’t really kill but acceleration may… “High speed motion picture camera frame: John Stapp is caught in the teeth of a massive deceleration. One might have expected that a test pilot or an astronaut candidate would be riding the sled; instead there was Stapp, a mild mannered physician and diligent physicist with a notable sense of humor. Source: US Air Force photo

  13. Free Fall • When any object is let go it falls toward the ground !! The force that causes the objects to fall is called gravity. • This acceleration on the Earth’s surface, caused by gravity, is typically written as “little” g • Any object, be it a baseball or an elephant, experiences the same acceleration (g) when it is dropped, thrown, spit, or hurled, i.e. g is a constant.

  14. Gravity facts: • g does not depend on the nature of the material ! • Galileo (1564-1642) figured this out without fancy clocks & rulers! • Feather & penny behave just the same in vacuum • Nominally, g= 9.81 m/s2 • At the equator g = 9.78 m/s2 • At the North pole g = 9.83 m/s2

  15. When throwing a ball straight up, which of the following is true about its velocity v and its acceleration a at the highest point in its path? Exercise 1Motion in One Dimension • Bothv = 0anda = 0 • v  0, but a = 0 • v = 0, but a  0 • None of the above y

  16. t a v v v t In driving from Madison to Chicago, initially my speed is at a constant 65 mph. After some time, I see an accident ahead of me on I-90 and must stop quickly so I decelerate increasingly fast until I stop. The magnitude of myacceleration vs timeis given by, Exercise 2 More complex Position vs. Time Graphs •  •   •   • Question: My velocity vs time graph looks most like which of the following ?

  17. Exercise 3 1D Freefall • Alice and Bill are standing at the top of a cliff of heightH. Both throw a ball with initial speedv0, Alice straightdownand Bill straightup. The speed of the balls when they hit the ground arevAandvBrespectively. • vA < vB • vA= vB • vA > vB Alice v0 Bill v0 H vA vB

  18. Exercise 3 1D Freefall : Graphical solution • Alice and Bill are standing at the top of a cliff of heightH. Both throw a ball with initial speedv0, Alice straightdownand Bill straightup. back at cliff cliff Dv= -g Dt turnaround point v0 vx t identical displacements (one + and one -) -v0 vground ground ground

  19. The graph at right shows the y velocity versus time graph for a ball. Gravity is acting downward in the -y direction and the x-axis is along the horizontal. Which explanation best fits the motion of the ball as shown by the velocity-time graph below? Home Exercise,1D Freefall • The ball is falling straight down, is caught, and is then thrown straight down with greater velocity. • The ball is rolling horizontally, stops, and then continues rolling. • The ball is rising straight up, hits the ceiling, bounces, and then falls straight down. • The ball is falling straight down, hits the floor, and then bounces straight up. • The ball is rising straight up, is caught and held for awhile, and then is thrown straight down.

  20. Problem Solution Method: Five Steps: • Focus the Problem - draw a picture – what are we asking for? • Describe the physics • what physics ideas are applicable • what are the relevant variables known and unknown • Plan the solution • what are the relevant physics equations • Execute the plan • solve in terms of variables • solve in terms of numbers • Evaluate the answer • are the dimensions and units correct? • do the numbers make sense?

  21. See you Wednesday Assignment: • For Wednesday, Read through Chapter 4.4

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