MSIT 413: Wireless Technologies Week 3

1. MSIT 413: Wireless TechnologiesWeek 3 Michael L. Honig Department of EECS Northwestern University October 2014

2. Cellular Frequency Assignments B A C E D G A C B F D G A C B E F D G C B E F D G A C B E D G A C B F G A D cell cluster (contains all channels) co-channel cells

3. B A C D G A F D B E F C B G A C D G F cell cluster Cellular Terminology • Cell cluster: group of N neighboring cells which use the complete set of available frequencies. • Cell cluster size: N • Frequency reuse factor: 1/N • Uplink or reverse link: Mobiles  Base station • Downlink or forward link: Base station  mobiles • Co-channel cells: cells which are assigned the same frequencies

4. Performance Measure:Signal-to-Interference-Plus-Noise Ratio (SINR) • Expressed in dB (10 log (SINR)) • Typically, the interference power dominates (ignore noise) • SINR  Signal-to-Interference Ratio (SIR or S/I) • Total interference power is the sum over all interferers: • More co-channel users  more interference

5. Voice Capacity • Defined as • Example: SE = 0.1 Erlang/MHz/km2 10 MHz needed to support 1 Erlang/km2(Note that 1 km2 may correspond to a cell.) • To convert Erlangs to users, must estimate traffic per user, e.g., if on average, each user is active 1/10 of the time, then 1 Erlang corresponds to 10 users. • Traffic per cell depends on: • Number of channels • Grade of Service (e.g., typically 2%) • S/I requirement (determined by cluster size N)

6. Effect of Sectorization • Does sectorization increase spectral efficiency?

7. Effect of Sectorization • For fixed N, sectorization • Increases the S/I • Reduces trunking efficiency • For example, with 99 channels per cell, 120o sectors divides this into 33 channels per sector, which reduces the number of Erlangs that can be supported for a given blocking probability. • Can we use sectorization to increase SE? • Yes, must also reduce N • Example: suppose the target S/I = 18 dB  N=7 for omni-directional antennas. With 120o sectors, the S/I increases to about 23 dB.Can reduce N from 7 to 4, and still maintain S/I > 18 dB.

8. Channel Allocation • Consider GSM: 25 MHz (simplex), 200 kHz channels 125 channels (1 is used for control signaling) • How to allocate channels to cells? Suburb (lightly loaded) Shopping mall Train station

9. Channel Allocation • Consider GSM: 25 MHz (simplex), 200 kHz channels 125 channels (1 is used for control signaling) • How to allocate channels to cells? • Objective: equalize blocking probability(target is around 2%) • Fixed channel allocation assignsfixed set of channels to each cell • Drawback? Suburb (lightly loaded) mall Train station

10. Channel Allocation • Consider GSM: 25 MHz (simplex), 200 kHz channels 125 channels (1 is used for control signaling) • How to allocate channels to cells? • Objective: equalize blocking probability(target is around 2%) • Fixed channel allocation assignsfixed set of channels to each cell. • Drawback: traffic is time-varying • Dynamic channel allocation varies the number of channels per cell, depending on the load. Suburb (lightly loaded) mall Train station

11. Dynamic Channel Allocation Channels already in use 2,6 1,3,4 new call: search for channel 1,3 5

12. Dynamic Channel Allocation • Channels assigned from complete set of available channels • Each user searches for a channel with high SINR (low interference) • No frequency planning! Channels already in use 2,6 1,3,4 new call: search for channel 1,3 4 5

13. 802.11b/g/n Channels • 14 overlapping (staggered) channels (11 in the U.S.) • Center frequencies are separated by 5 MHz • Bandwidth/interference controlled by “spectral mask” • 30 dB attenuation 11 MHz from center frequency • 50 dB attenuation 22 MHz from center frequency Comparison table Channels: 1 6 11

14. Dynamic Channel Allocation: 802.11b/g/n Channel 11 Channel 1 Channel 6

15. Dynamic Channel Allocation: 802.11b/g/n Channel 11 Channel 1 Channel 6 interference Add new router Channel 6

16. Dynamic Channel Allocation: 802.11b/g/n Channel 11 Switches to channel 1 Channel 1 interference Channel 6

17. Dynamic Channel Allocation: 802.11b/g/n Channel 11 Switches to channel 6 channel 1 interference Channel 6

18. Dynamic Channel Allocation: 802.11b/g/n Channel 11 channel 6 channel 1 interference Switches to channel 1 Dynamic channel assignment becomes unstable!

19. Overlapping Channel Assignment Channel 11 channel 6 channel 1 Interference (less than before) Interference (less than before) power Channel 3 Channels: 1 3 6 frequency

20. FCA vs. DCA FCA DCA • Moderate/High complexity • Must monitor channel occupancy,traffic distribution, S/I (centralized) • Better under light/moderate traffic • Insensitive to changes in traffic • Stable grade of service • Low probability of outage (call termination) • Suitable for micro-cellular systems(e.g., cordless) • Moderate/high call setup delay • No frequency planning • Assignment can be centralized or distributed • Low complexity • Better under heavy traffic • Sensitive to changes in traffic • Variable grade of service • Higher probability of outage • Suitable for macro-cellular systems(e.g., cellular) • Low call setup delay • Requires careful frequency planning • Centralized assignment

21. Why Study Radio Propagation? • To determine coverage • Must determine path loss • Function of • Frequency • Distance • Terrain (office building, urban, hilly, rural, etc.) Can we use the same channels? Need “large-scale” models

22. Why Study Radio Propagation?

23. Why Study Radio Propagation? • To enable robust communications • How can we guarantee reliable communications? • What data rate can we provide? • Must determine signal statistics: • Probability of outage • Duration of outage Received Power Deep fades may cause an outage time Need “small-scale” models

24. Will provide answers to… • What are the major causes of attenuation and fading? • Why does the achievable data rate decrease with mobility? • Why are wireless systems evolving to wider bandwidths (spread spectrum and OFDM)? • Why does the accuracy of location tracking methods increase with wider bandwidths?

25. Propagation Key Words • Large-scale effects • Path-loss exponent • Shadow fading • Small-scale effects • Rayleigh fading • Doppler shift and Doppler spectrum • Coherence time / fast vs slow fading • Narrowband vs wideband signals • Multipath delay spread and coherence bandwidth • Frequency-selective fading and frequency diversity

26. Propagation Mechanisms:1. Free Space distance d reference distance d0=1 Reference power at reference distance d0 Path loss exponent=2 P0 In dB: Pr = P0 (dB) – 20 log (d) slope = -20 dB per decade Pr (dB) P0 = Gt Gr (/4)2 log (d) 0 wavelength antenna gains

27. Wavelength • Wavelength >> size of object  signal penetrates object. • Wavelength << size of object  signal is absorbed and/or reflected by object. • Large-scale effects refers to propagation over distances of many wavelengths.Small-scale effects refers to propagation over a distances of a fraction of a wavelength.  (meters) = c (speed of light) / frequency

28. Dipole Antenna 802.11 dipole antenna cable from transmitter wire (radiator)

29. Radiation Pattern: Dipole Antenna Dipole axis Dipole axis Electromagnetic wave radiates outfrom the dipole axis. Cross-section of doughnut pattern

30. Antenna Gain Pattern Red curve shows the antenna gain versus angle relative to an isotropic pattern (perfect circle) in dB. Often referred to as dBi, dB “isotropic”. -5 dB (factor of about 1/3) relative to isotropic pattern Dipole pattern (close to isotropic)

31. Antenna Gain Pattern Dipole pattern (vertical) 90 degree sector

32. Path loss ~ 13 dB / 100 m or 130 dB / 1 km Increases linearly with distance Requires repeaters for long distances Path loss ~ 30 dB for the first meter + 20 dB / decade 70 dB / 100 meters (2 decades) 90 dB / 1 km(3 decades) 130 dB / 100 km! Increases as log (distance) Repeaters are infeasible for satellites Attenuation: Wireless vs. Wired 1 GHz Radio (free space) Unshielded Twisted Pair Short distance  Wired has less path loss. Large distance  Wireless has less path loss.

33. Incident E-M wave reflected wave q q Length of boundary >> wavelength l transmitted wave Propagation Mechanisms 2. Reflection 3. Diffraction 4. Scattering Signal loss depends on geometry Hill

34. Why Use > 500 MHz?

35. Why Use > 500 MHz? • There is more spectrum available above 500 MHz. • Lower frequencies require larger antennas • Antenna dimension is on the order of awavelength = (speed of light/frequency) = 0.6 M @ 500 MHz • Path loss increases with frequency for the first meter • 10’s of GHz: signals are confined locally • More than 60 GHz: attenuation is too large(oxygen absorbs signal)

36. 700 MHz Auction • Broadcast TV channels 52-69 relocated in Feb. 2009. • 6 MHz channels occupying 698 – 806 MHz • Different bands were auctioned separately: • “A” and “B” bands: for exclusive use (like cellular bands) • “C” band (11 MHz): must support open handsets, software apps • “D” band (5 MHz): shared with public safety (has priority) • Commenced January 24, 2008, ended in March

37. Why all the Hubbub? • This band has excellent propagation characteristics for cellular types of services (“beach-front property”). • Rules for spectrum sharing can be redefined…

39. C Band Debate • Service providers in the U.S. did not allow any services, applications, or handsets from unauthorized 3rd party vendors. • Google asked the FCC to stipulate that whoever wins the spectrum must support open applications, open devices, open services, open networks (net neutrality for wireless). • Verizon wants to maintain “walled-garden”. • FCC stipulated open applications and devices, but not open services and networks: spectrum owner must allow devices or applications to connect to the network as long as they do not cause harm to the network • Aggressive build-out requirements: • Significant coverage requirement in four years, which continues to grow throughout the 10-year term of the license.

40. Sold to… • Verizon • Other winners: AT&T (B block), Qualcomm (B, E blocks) • Total revenue: $19.6 B • $9.6 B from Verizon, $6.6 B from AT&T • Implications for open access, competition?

41. D Band Rules • Winner gets to use both D band and adjacent public service band (additional 12 MHz!), but service can be preempted by public safety in emergencies. • Winner must build out public safety network:must provide service to 75% of the population in 4 years, 95% in 7 years, 99.3% in 10 years • Minimum bid: $1.3 B; estimated cost to deploy network: $10-12 B • Any takers? …

42. D Band Rules • Winner gets to use both D band and adjacent public service band (additional 12 MHz!), but service can be preempted by public safety in emergencies. • Winner must build out public safety network:must provide service to 75% of the population in 4 years, 95% in 7 years, 99.3% in 10 years • Minimum bid: $1.3 B; estimated cost to deploy network: $10-12 B • Any takers? … Nope! Highest bid was well below reserve…

43. T T Radio Channels Troposcatter Microwave LOS Mobile radio Indoor radio

44. Sinusoidal Signal Electromagnetic wave s(t) = A sin (2  f t + ) Time delay = 12, Phase shift  = 12/50 cycle = 86.4 degrees Amplitude A=1 s(t) Period= 50 sec, frequency f = 1/50 cycle/sec Time t (seconds)

45. Two Signal Paths s1(t) s2(t) Received signal r(t) = s1(t) + s2(t) Suppose s1(t) = sin 2f t. Then s2(t) = h s1(t - ) = h sin 2f (t - ) attenuation (e.g., h could be ½) delay (e.g.,  could be 1 microsec.)

46. Sinusoid Addition (Constructive) s1(t) r(t) + = s2(t) Adding two sinusoids with the same frequency gives another sinusoid with the same frequency!

47. Sinusoid Addition (Destructive) s1(t) r(t) + = s2(t) Signal is faded.

48. Ceiling Hypothetical large indoor environment Indoor Propagation Measurements Normalized received power vs. distance

49. Ceiling Hypothetical large indoor environment Indoor Propagation Measurements Large-scale variation (average over many wavelengths) Normalized received power vs. distance

50. Ceiling Hypothetical large indoor environment Indoor Propagation Measurements Small-scale variations (over fractions of a wavelength) Normalized received power vs. distance