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InClass

High School. PHYSICS. InClass. by SSL Technologies. with S. Lancione. Exercise-49. Curved mirrors. Part 2 /2. Curved Mirrors. PART-2 /2. The mirror equation is a geometrical derivation for solving problems with curved mirrors. Where: f = focal length (in metres)

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  1. High School PHYSICS InClass by SSL Technologies with S. Lancione Exercise-49 Curved mirrors Part 2 /2

  2. Curved Mirrors PART-2 /2 The mirror equation is a geometrical derivation for solving problems with curved mirrors. Where: f = focal length (in metres) do = Object distance (in metres) di = Image distance (in metres) and Where: M = magnification factor (no units) hi = height of image (in metres) ho = height of object (in metres) Click

  3. Curved Mirrors PART-2 Where: f = focal length (in metres) do = Object distance (in metres) di = Image distance (in metres) Be sure to observe the following sign conventions when usingthe mirror formula: All distances are measured from the vertex of a curved mirror. Distances of objects and real images are positive. Distances of virtual images are negative. Object and image heights are positive when upright and negative when inverted. Parabolic mirrors are used as reflectors for searchlights, flashlights, projectors and automobile headlights. Click

  4. REMEMBER When M is less than 1,the image is reduced. When M is negative,the image is inverted. Click

  5. EXERCISES

  6. Question-1 An object is 60 cm from a converging mirror whose radius of curvature is 30 cm. Determine the characteristics of the image. Real Type (real or virtual): _______________ Location: _______________ Magnification: _______________ Attitude (upright/inverted): _______________ 20 cm (in front of mirror) -0.33 (inverted and smaller than object) Inverted Click Click

  7. Question-2 An object is 25 cm from a concave mirror whose focal length is 15 cm. Determine the characteristics of the image. Real Type (real or virtual): _______________ Location: _______________ Magnification: _______________ Attitude (upright/inverted): _______________ 37.5 cm (in front of mirror) -1.5 (inverted and larger than object) Inverted Click Click

  8. Question-3 Negative sign indicates virtual image An object is placed 7.5 cm from a concave mirror that has a focal length of 15 cm. Determine the characteristics of the image. Virtual Type (real or virtual): _______________ Location: _______________ Magnification: _______________ Attitude (upright/inverted): _______________ 15 cm (behind mirror) 2 (upright and larger than object) Upright Click Click

  9. Question-4 Negative sign indicates virtual image A converging mirror has a focal length of 15 cm. Where would you place an object in front of this mirror in order to produce an upright, virtual image, twice as tall as the object? Answer Click Click

  10. Question-5 This means a virtual image (di is negative). What is the focal length of a concave mirror when an object that is placed 2 cm in front of the mirror produces an image that is seen 5 cm behind the mirror? Answer Click Click

  11. Question-6 A concave mirror has a focal length of 30 cm. A square object, 4 cm per edge, is situated with its center 10 cm in front of the mirror. Determine: a) The position (center) of the image. Click Click

  12. Question-6 A concave mirror has a focal length of 30 cm. A square object, 4 cm per edge, is situated with its center 10 cm in front of the mirror. Determine: b) The area of the image. Click Click

  13. Question-7 Illustrated below is an object situated in front of a convexmirror. Graphically, find the image and state its characteristics. . NOTE Convex mirrors always produceimages that are virtual, uprightand reduced. The image is virtual, upright, reduced and located behind the mirror. Click Click

  14. Question-8 d i An object is placed 10 cm in front of a convexmirror whose focal length is 15 cm. Determine the characteristics of the image. The image is virtual (since di is negative), upright (since M is positive), smaller than the object (since M = 0.6) and located behind the mirror. Click Click

  15. Question-9 When an object is 30 cm in front of a concavemirror, its image is real and situated 15 cm from the mirror. Determine the location of the image when the object is placed 6.0 cm from the mirror. The image is virtual and located behind mirror. Answer Click Click

  16. Question-10 Fill in the four (4) missing quantities in the table below: 1 2 3 cm 8 cm 3 4 -23.3 cm 0.7 cm Click Click

  17. Question-11 An object is placed in front of a convex mirror as illustrated below. Draw and label the light rays necessary to locate the image. Reflected ray Incident ray Extended ray Incident ray Image Extended ray Reflected ray Image is virtual, upright and reduced. Click

  18. Question-12 An object 45.0 cm high is placed in front of a convex mirror whosefocal length is 30.0 cm. If a virtual image 15.0 cm high is formed, determine the distancethe object is from the mirror. REMINDERConvex mirrors have a negative focal length. Virtual images have a negative distance. Step-1 Calculate di Given A) 10.0 cm B) 20.0 cm C) 60.0 cm D) 90.0 cm E) 120.0 cm Step-2 Calculate do Click

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