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Triangles and Parallelograms Lesson 11.2

Triangles and Parallelograms Lesson 11.2. M. 13cm. 9cm. 6cm. H. T. Theorem 100: The area of a parallelogram is equal to the product of the base and the height. A = bh. h. b. A. Find the area of MATH. M. 13cm. 9cm. 6cm. H. T. A.

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Triangles and Parallelograms Lesson 11.2

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  1. Triangles and ParallelogramsLesson 11.2

  2. M 13cm 9cm 6cm H T Theorem 100: The area of a parallelogram is equal to the product of the base and the height. A = bh h b A Find the area of MATH

  3. M 13cm 9cm 6cm H T A You will receive one point for each line, plus the correct unit. Minimum 3 lines. A = bh = 13(6) = 78cm2

  4. Theorem 101: The area of a triangle is equal to one-half the product of a base and the height (or altitude) for that base. A = bh Where b is the length of the base and h is the altitude. Altitude may be inside, outside or the leg of the triangle. The base may not always be at the bottom. h b

  5. 15 x Find the area of this triangle. 12mm 8mm A = 48 mm2 Find the base of a triangle with an altitude of 15 and area 60. x = 8

  6. 14 6 60˚ Find the area of a parallelogram whose sides are 14 and 6 and whose acute angle is 60˚. Draw and label. D U C K How will you find the height?

  7. 14 6 60˚ D U C K S Drop line DS to form a 30-60-90 triangle. Line DS is A = bh = 14( ) = 42

  8. Team Activity: Draw a parallelogram that has a perimeter of 40 units . What is its area? Which team created the parallelogram with the GREATEST area? What shape is it?

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