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Lecture 17: Geodetic Datums and a little Linear Regression

Lecture 17: Geodetic Datums and a little Linear Regression. GISC-3325 24 March 2008. Update. Reading for next few classes Chapters Eight and Nine Start reading GPS Positioning Guide Chapters 1-3. Exam results and answers are posted to class web page.

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Lecture 17: Geodetic Datums and a little Linear Regression

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  1. Lecture 17: Geodetic Datums and a little Linear Regression GISC-3325 24 March 2008

  2. Update • Reading for next few classes • Chapters Eight and Nine • Start reading GPS Positioning Guide Chapters 1-3. • Exam results and answers are posted to class web page. • Extra credit opportunities are available and should be discussed with Instructor

  3. Azimuth for DRISCOLL to DRISCOLL RM 1 is taken from the datasheet.

  4. Datum • “A datum is any quantity or set of quantities that may serve as a referent or basis for calculation of other quantities.” source: NGS Glossary • Historically there were separate bases for horizontal and vertical datum.

  5. Vertical Datum • A set of fundamental elevations to which other elevations are referred. • National Geodetic Vertical Datum of 1929 (NGVD 29) formerly known as Mean Sea Level Datum of 1929. • Because mean sea level varies too much! • North American Vertical Datum of 1988 • Readjustment not referenced to mean sea level.

  6. Global Sea Level

  7. NGVD 29 • Define by heights at 26 tide stations in the US and Canada. • Gages connected to vertical network by leveling • Water-level transfers to connect leveling across the Great Lakes • Used normal orthometric heights • scaled geopotential numbers using normal gravity

  8. Problems with NGVD 29

  9. NAVD 88 • Datum based on an equipotential surface • Minimally constrained at one point: Father Point/Rimouski on St. Lawrence Seaway • 1.3 million kilometers of level data • Heights of 585,000 permanent monuments

  10. Father Point/Rimouski

  11. Elements of NAVD 88 • Detected and removed height errors due to blunders • Minimized effects of systematic errors in leveling data • improved procedures better modeling • Re-monumentation and new leveling • Removal of height discrepancies caused by inconsistent constraints.

  12. Height Relations h – H – N = zero + errors

  13. H h N h – H – N ≠ 0 WHY?

  14. NAVD 88 height by GPS = 1.83 m NAVD 88 height adjusted = 1.973 m Difference = 0.14 m

  15. New vertical datum to be based on h (ellipsoid heights) and N (gravimetric geoid model). Remember: h – H – N = 0 plus errors

  16. Vertical Datum Transformations • First choice: Estimate heights using original leveling data in least squares • Second choice: Rigorous transformation using datum conversion correctors estimated by adjustment constraints and differences • Third option: VERTCON

  17. Linear Regression • Linear regression attempts to model the relationship between two variables by fitting a linear equation to observed data. • A linear regression line has an equation of the form Y = mX + b, where X is the explanatory variable and Y is the dependent variable. The slope of the line is m, and b is the intercept (the value of y when x = 0).

  18. Results in Excel http://phoenix.phys.clemson.edu/tutorials/excel/regression.html

  19. Why not Matlab?

  20. Matlab to the rescue!

  21. Rod Calibration

  22. Two-Plane Method of Interpolating Heights (Problem 8.3) • We can approximate the shift at an unknown point (when observations are unavailable) using least squares methods. • Need minimum of four points with known elevations in both vertical datums. • Need plane coordinates for all points. • Calculates rotation angles in both planes (N-S and E-W) as well as the vertical shift.

  23. Problem 8.3 in text

  24. Function model • (NAVD88i-NGVD29i)=αE(Ni-N0)+ αN(Ei-E0)+tZ • Where we compute the following (all values in meters): • NAVD88i-NGVD29i =difference in heights • Ni-N0 = is difference of each North coordinate of known points from centroid • Ei-E0 = is difference of each East coordinate of known points from centroid

  25. Solving Problem • Determine the mean value (centroid) for N and E coordinates (use known points only) • N0: 58762 E0: 1398370 (wrong in text) • Determine NAVD 88 - NGVD 29 for points with values in both systems. Note signs! ΔQ 547 = 1.085 Δ A 15 = 1.094 Δ AIRPORT 2: = 1.106 Δ NORTH BASE = 1.085

  26. Compute differences from centroid

  27. Compute parameters • B the design matrix consists of three columns: • Col.1: difference in Northings from centroid • Col.2: difference in Eastings from centroid • Col.3: all ones • F the observation matrix • Vector of height differences • Parameters are computed by least squares: (BTB)-1BTf

  28. Applying parameters • Our matrix inversion solved for rotations in E and N as well as shift in height. • Compute the shift at our location using our functional model: αE(Ni-N0)+ αN(Ei-E0)+tZ • Result is the magnitude of the shift. • We calculate the new height by adding the shift to the height in the old system.

  29. We validate the accuracy of our result by computing the variances.

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