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Remembering: Molarity and Stoichiometry

Remembering: Molarity and Stoichiometry. Because we know you brain is getting full!!!. Molarity = moles (Molar) or (M) litres. Calculate the molarity of 18 moles of LiBr dissolved in 6.0 L. = 18 moles 6.0 L = 3.0 M.

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Remembering: Molarity and Stoichiometry

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  1. Remembering:Molarity and Stoichiometry Because we know you brain is getting full!!!

  2. Molarity = moles (Molar) or (M) litres

  3. Calculate the molarity of 18 moles of LiBr dissolved in 6.0 L. = 18 moles 6.0 L = 3.0 M

  4. How many moles of AlF3 are there in 20.5 L of a 0.172 M solution?

  5. How many moles of AlF3 are there in 20.5 L of a 0.172 M solution? 20.5 L x

  6. How many moles of AlF3 are there in 20.5 L of a 0.172 M solution? 20.5 L x 1 L

  7. How many moles of AlF3 are there in 20.5 L of a 0.172 M solution? 20.5 L x 0.172 mole 1 L

  8. How many moles of AlF3 are there in 20.5 L of a 0.172 M solution? 20.5 L x 0.172 mole = 3.53 moles 1 L

  9. STOICHIOMETRY

  10. Stoichiometry is where you use the balancing coefficientsto create a ratio between two different compounds in a chemical reaction.

  11. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2

  12. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g

  13. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g 2 4

  14. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g 105 g Fe

  15. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g 105 g Fe x 1 mole 55.8 g

  16. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g 105 g Fe x 1 mole x 2 mole Fe2O 55.8 g 4 mole Fe

  17. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g 105 g Fe x 1 mole x 2 mole Fe2Ox 159.6 g 55.8 g 4 mole Fe 1 mole

  18. 1. How many grams Fe2O3 of are required to produce 105 g of Fe?2Fe2O3 + 3C → 4Fe + 3CO2?g 105 g 105 g Fe x 1 mole x 2 mole Fe2Ox 159.6 g = 150. g 55.8 g 4 mole Fe 1 mole

  19. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2

  20. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2 65.2 g ? g

  21. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2 65.2 g ? g 65.2 g x Na2CO3 2 1

  22. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2 65.2 g ? g 65.2 g x Na2CO3 x 1 mol Na2CO3 106.0 g Na2CO3 2 1

  23. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2 65.2 g ? g 65.2 g x Na2CO3 x 1 mol Na2CO3 x 2 mol NaCl 106.0 g Na2CO3 1 mol Na2CO3 2 1

  24. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2 65.2 g ? g 65.2 g x Na2CO3 x 1 mol Na2CO3 x 2 mol NaCl x 58.5 g NaCl 106.0 g Na2CO3 1 mol Na2CO3 1 mol NaCl 2 1

  25. How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na2CO3 + 2 HCl → 2 NaCl+ 1 H2O+ 1 CO2 65.2 g ? g 65.2 g x Na2CO3 x 1 mol Na2CO3 x 2 mol NaClx 58.5 g NaCl = 72.0 g 106.0 g Na2CO3 1 mol Na2CO3 1 mol NaCl 2 1

  26. 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution? 2 HCl + 1 Ba(OH)2→ 2 H2O + 1 BaCl2

  27. 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution? 2 HCl + 1 Ba(OH)2→ 2 H2O + 1 BaCl2 30.2 L ? L 30.2 L HCl 1 2

  28. 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution? 2 HCl + 1 Ba(OH)2→ 2 H2O + 1 BaCl2 30.2 L ? L 30.2 L HCl x 1 mol HCl 22.4 L 1 2

  29. 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution? 2 HCl + 1 Ba(OH)2→ 2 H2O + 1 BaCl2 30.2 L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH)2 22.4 L 2 mol HCl 1 2

  30. 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution? 2 HCl + 1 Ba(OH)2→ 2 H2O + 1 BaCl2 30.2 L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH)2 x 1 L Ba(OH)2 = 22.4 L 2 mol HCl 0.200 mol Ba(OH)2 1 2

  31. 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH)2 will neutralize this solution? 2 HCl + 1 Ba(OH)2→ 2 H2O + 1 BaCl2 30.2 L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH)2 x 1 L Ba(OH)2 = 3.37 L 22.4 L 2 mol HCl 0.200 mol Ba(OH)2 1 2

  32. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4

  33. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4 0.100 L ? L

  34. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4 0.100 L ? L 0.1000 L H2SO4

  35. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4 0.100 L ? L 0.1000 L H2SO4 x 0.200 mol H2SO4 1L

  36. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4 0.100 L ? L 0.1000 L H2SO4 x 0.200 mol H2SO4 x 2 mol KOH 1L 1 mol H2SO4

  37. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4 0.100 L ? L 0.1000 L H2SO4 x 0.200 mol H2SO4 x 2 mol KOHx 1 L KOH 1L 1 mol H2SO40.300 mol KOH

  38. 250. mL of water is added to 100.0 mL of 0.200 M H2SO4. What volume of 0.300 M KOH will neutralize it? 1 H2SO4 + 2 KOH → 2 HOH + 1 K2SO4 0.100 L ? L 0.1000 L H2SO4 x 0.200 mol H2SO4 x 2 mol KOHx 1 L KOH 1L 1 mol H2SO40.300 mol KOH = 0.133 L of KOH

  39. Homework: Worksheet #4 (in Molarity Unit)

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