1 / 30

Unit 3-1 wave-particle duality of electron and light

Unit 3-1 wave-particle duality of electron and light. Chap 7. The Dilemma of the Atom. Electrons outside the nucleus are attracted to the protons in the nucleus Charged particles moving in curved paths lose energy What keeps the atom from collapsing?. Answering the Dilemma of the Atom.

orinda
Download Presentation

Unit 3-1 wave-particle duality of electron and light

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Unit 3-1 wave-particle duality of electron and light Chap 7

  2. The Dilemma of the Atom • Electrons outside the nucleus are attracted to the protons in the nucleus • Charged particles moving in curved paths lose energy • What keeps the atom from collapsing?

  3. Answering the Dilemma of the Atom • Treat electrons as both waves and particles, called wave-particle duality • Like light.

  4. Matter and energy • Our world is made of two things: • Matter : whichever has mass. • Energy : • Electricity • Heat • Waves: light, sound

  5. Waves • the distance between corresponding points on adjacent waves is the wavelength (), in unit of meter • The number of waves passing a given point per unit of time is the frequency (), in unit of s-1. • The time needed to pass a wavelength is the period (T),in unit of second. • T= 1/  • For waves traveling at the same velocity, the longer the wavelength, the smaller the frequency.

  6. Electromagnetic radiation propagates through space as a wave moving at the speed of light. c =  c = speed of light, a constant (3.00 x 108 m/s)  = frequency, in units of hertz (hz, sec-1)  = wavelength, in meters

  7. Diffraction – a special wave feature • when traveling waves encounter an obstacle or opening in a barrier that is about the same size as the wavelength, they bend around it – this is called diffraction • traveling particles do not diffract Tro, Chemistry: A Molecular Approach

  8. Diffraction • the diffraction of light through two slits separated by a distance comparable to the wavelength results in an interference pattern of the diffracted waves • an interference pattern is a characteristic of all light waves

  9. however, electrons actually present an interference pattern, demonstrating the behave like waves Electron Diffraction Tro, Chemistry: A Molecular Approach

  10. Electromagnetic Radiations (light) • All electromagnetic radiation travels at the same velocity: the speed of light (c), 3.00  108 m/s. • Therefore, c = /T= • Remember the sequence and visible light wavelength!

  11. The particle nature of light • The wave nature of light does not explain how an object can glow when its temperature increases. • Max Planck explained it by assuming that energy comes in packets called quanta, which is carried by photon.

  12. Photon a particle of light. Electromagnetic radiation ALL light. Visible AND invisible visible light , x-rays, gamma rays, radio waves, microwaves, ultraviolet rays, infrared.

  13. The energy (E ) carried by each photon of electromagnetic radiation is directly proportional to the frequency () of the radiation. E = h E= Energy, in units of Joules (kg·m2/s2) h= Planck’s constant (6.626 x 10-34 J·s) = frequency, in units of hertz (hz) or sec-1

  14. The Nature of light • Therefore, if one knows the wavelength of light, one can calculate the energy in one photon, or packet, of that light: c =  E = h

  15. Wavelength Table Long Wavelength = Low Frequency = Low ENERGY Short Wavelength = High Frequency = High ENERGY

  16. Homework • Page 314, question 39, 41 a and b, 43

  17. Bohr Model of H Atom and emission spectra

  18. Hg He H Exciting Gas Atoms to Emit Light with Electrical Energy Tro, Chemistry: A Molecular Approach

  19. Emission Spectra Tro, Chemistry: A Molecular Approach

  20. The emission spectra • When light goes through a certain chemical gas: • One does not observe a continuous spectrum, as one gets from a white light source. • Only a line spectrum of discrete wavelengths is observed.

  21. Bohr Model of H Atoms • Electrons orbit about nucleus on energy level /shell (n). • Each energy level has a defined distance to nucleus. • Electrons can jump from one level or another if receiving or releasing energy.

  22. Bohr’s model of H atom • The energy of one electron on the shell n, En can be calculated by the following formula: • En = • 2.178  10−18 J= RH,called Rydberg constant.

  23. Bohr’s model of H atom The energy absorbed or emitted from the process of electron promotion or demotion can be calculated by the equation: Ef -Ei =E = −2.178x10-18 ni and nf are the initial and final energy levels of the electron.

  24. 1 nf2 ( ) - = −RH 1 ni2 Predicting emission spectrum of Hydrogen • the wavelengths of lines in the emission spectrum of hydrogen can be predicted by calculating the difference in energy between any two states • for an electron in energy state n, there are (n – 1) energy states it can transition to, therefore (n – 1) lines it can generate • the Bohr Model can predict these lines very accurately

  25. Hydrogen Energy Transitions

  26. ni, nf DEatom Ephoton l Example 7.7- Calculate the wavelength of light emitted when the hydrogen electron transitions from n = 6 to n = 5 Given: Find: ni = 6, nf = 5 l, m Concept Plan: Relationships: E=hc/l, En = -2.18 x 10-18 J (1/n2) DEatom = -Ephoton Solve: Ephoton = -(-2.6644 x 10-20 J) = 2.6644 x 10-20 J Check: the unit is correct, the wavelength is in the infrared, which is appropriate because less energy than 4→2 (in the visible)

  27. Practice – Calculate the wavelength of light emitted when the hydrogen electron transitions from n = 2 to n = 1

  28. ni, nf DEatom Ephoton l Calculate the wavelength of light emitted when the hydrogen electron transitions from n = 2 to n = 1 Given: Find: ni = 2, nf = 1 l, m Concept Plan: Relationships: E=hc/l, En = -2.18 x 10-18 J (1/n2) DEatom = -Ephoton Solve: Ephoton = -(-1.64 x 10-18 J) = 1.64 x 10-18 J Check: the unit is correct, the wavelength is in the UV, which is appropriate because more energy than 3→2 (in the visible)

  29. Bohr model and quantum mechanical model • Bohr model failed to predict other elements’ emission spectrum. Why? • There is only one e- in H. Each shell / energy level (n) is degenerate (unified). • In multiple-electron atoms, there are subshells have hold different energy, in each shell. • His model is replaced by quantum mechanical model. • His model is only useful to predict the emission spectrum of H.

  30. Homework • Page 315 64, 67 b and c.

More Related