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Projectile Motion

Projectile Motion. Projectiles launched at an angle. Velocity in the x direction is constant Velocity in the y direction changes due to gravity. v. v y. q. v x. v x is constant, v y is equal and opposite at equal times from the highest point. Velocity in the x direction. v i. q.

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Projectile Motion

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  1. Projectile Motion Projectiles launched at an angle

  2. Velocity in the x direction is constant Velocity in the y direction changes due to gravity

  3. v vy q vx

  4. vx is constant, vy is equal and opposite at equal times from the highest point

  5. Velocity in the x direction vi q vx = vi(cosq) vx = Dx/Dt Dx = vi(cosq)Dt

  6. Velocity in the y direction vy = vi(sinq) vi vy = Dy/Dt Dy = vi(sinq)Dt +1/2gDt2 q

  7. Dy = vi(sinq)Dt +1/2gDt2 1/2Dt Dy q Dx

  8. 1. I throw a basketball at an angle of 58° above the horizontal with a velocity of 24.36 m/s. What is the a) time it is in the air? b) distance it goes? and c) maximum height? a) Dy = vi(sinq)Dt + 1/2g(Dt)2 = 0 Dt = -2vi(sinq)/g = -2(24.36m/s)(sin58°)/-9.81m/s2 = 4.21s b) Dx = vi(cosq)Dt = (24.36m/s)(cos58°)(4.21s) = 54.3m c) Dymax = vi(sinq)(1/2)Dt + 1/2g(1/2Dt)2 = (24.36m/s)(sin58°)(2.105s) + 1/2g(2.105)2 = 21.7m -9.81m/s2

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