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Quadratic Equations P.7

Quadratic Equations P.7. A quadratic equation in x is an equation that can be written in the standard form ax 2 + bx + c = 0 where a , b , and c are real numbers with a not equal to 0. A quadratic equation in x is also called a second-degree polynomial equation in x.

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Quadratic Equations P.7

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  1. Quadratic EquationsP.7

  2. A quadratic equation in x is an equation that can be written in the standard form ax2+bx+c= 0 where a, b, and c are real numbers with a not equal to 0. A quadratic equation in x is also called a second-degree polynomial equation in x. Definition of a Quadratic Equation

  3. If the product of two algebraic expressions is zero, then at least one of the factors is equal to zero. If AB= 0, then A= 0 or B= 0. The Zero-Product Principle

  4. Solving a Quadratic Equation by Factoring • If necessary, rewrite the equation in the form ax2+bx+c= 0, moving all terms to one side, thereby obtaining zero on the other side. • Factor. • Apply the zero-product principle, setting each factor equal to zero. • Solve the equations in step 3. • Check the solutions in the original equation.

  5. Text Example • Solve 2x2+ 7x= 4 by factoring and then using the zero-product principle. Step 1Move all terms to one side and obtain zero on the other side. Subtract 4 from both sides and write the equation in standard form. 2x2+ 7x- 4= 4 - 4 2x2+ 7x- 4 = 0 Step 2Factor. 2x2+ 7x- 4 = 0 (2x- 1)(x+ 4) = 0

  6. Solution cont. • Solve 2x2+ 7x= 4 by factoring and then using the zero-product principle. Steps 3 and 4Set each factor equal to zero and solve each resulting equation. 2 x- 1 = 0 or x+ 4 = 0 2 x= 1 x= -4 x = 1/2 Steps 5 check your solution

  7. (2x + -3)(2x + 1) = 5 4x2 - 4x - 3 = 5 4x2 - 4x - 8 = 0 4(x2-x-2)=0 4(x - 2)*(x + 1) = 0 x - 2 = 0, and x + 1 = 0 So x = 2, or -1 Example

  8. If u is an algebraic expression and d is a positive real number, then u2 = d has exactly two solutions. If u2 = d, then u = d or u = -d Equivalently, If u2 = d then u = d The Square Root Method

  9. If x2 + bx is a binomial then by adding (b/2) 2, which is the square of half the coefficient of x, a perfect square trinomial will result. That is, x2 + bx + (b/2)2 = (x + b/2)2 Completing the Square

  10. What term should be added to the binomial x2 + 8x so that it becomes a perfect square trinomial? Then write and factor the trinomial. The term that should be added is the square of half the coefficient of x. The coefficient of x is 8. Thus, (8/2)2 = 42. A perfect square trinomial is the result. x2 + 8x + 42 = x2 + 8x + 16 = (x + 4)2 Text Example

  11. B divided by 2, squared Don’t forget to add to both sides

  12. Quadratic Formula

  13. Discriminant b2 – 4ac Kinds of solutions to ax2+ bx+ c = 0 Graph of y= ax2+ bx+ c b2 – 4ac > 0 Two unequal real solutions Two x-intercepts b2 – 4ac = 0 One real solution (a repeated solution) One x-intercept b2 – 4ac < 0 No real solution; two complex imaginary solutions No x-intercepts The Discriminant and the Kinds of Solutions to ax2 + bx +c = 0

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