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CH 6

CH 6. Work - Work is calculated by multiplying the force applied by the distance the object moves while the force is being applied. W = Fs.

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CH 6

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  1. CH 6

  2. Work -Work is calculated by multiplying the force applied by the distance the object moves while the force is being applied. W = Fs

  3. Ex. 4 - A flatbed truck accelerating at a = +1.5 m/s2 is carrying a 120 kg crate. The crate does not slip as the truck moves s = 65 m. What is the total work done on the crate by all the forces acting on it?

  4. The Work-Energy Theorem.W = KEf - KE0 = 1/2 mvf2- 1/2 mv02

  5. Ex. 6 - A 54 kg skier is coasting down a 25° slope. A kinetic frictional force of fk = 70 N opposes her motion. Her initial speed is v0 = 3.6 m/s. Ignoring air resistance, determine the speed vf at a displacement 57 m downhill.

  6. Gravitational Potential Energy is energy due to the distance an object is able to fall.PE = mghPE is also measured in joules.

  7. The work done by the gravitational force on an object does not depend on the path taken by the object. This makes gravitational force a conservative force.

  8. Conservation of Mechanical EnergyThe total mechanical energy (E = KE + PE) of an object remains constant as the object moves, provided that the net work done by external nonconservative forces is zero.

  9. Ex. 9 - A motorcyclist drives horizontally off a cliff to leap across a canyon. When he drives off, he has a speed of 38.0 m/s. Find the speed with which the cycle strikes the ground on the other side if he is 35 m below his starting point when he strikes the ground.

  10. Ex. 10 - A 6.00-m rope is tied to a tree limb and used as a swing. A person starts from rest with the rope held in a horizontal orientation. Determine how fast the person is moving at the lowest point on the circular arc of the swing.

  11. Power is the rate at which work is done.P = W/tThe unit is the joule/second, which is called the watt.1 horsepower = 746 watts

  12. W/t = Fs/tW/t is power, and s/t is average speed v, so P = Fv

  13. Ex. 15 - A 1.10 x 103 kg car, starting from rest, accelerates for 5.00 s. The magnitude of the acceleration is a = 4.60 m/s2. Determine the average power generated by the net force that accelerates the vehicle.

  14. Energy of all types can be converted from one form to another.The Principle of Conservation of Energy:Energy can be neither created nor destroyed, but can only be converted from one form to another.

  15. CH 7

  16. The impulse of a force is the product of the average force and the time interval during which the force acts.Impulse = FaveΔtThe unit is the newton•second (N•s)

  17. The linear momentum p of an object is the product of the object’s mass m and the velocity v. p = mv The unit is the kilogram•meter/second (kg•m/s)

  18. The impulse-momentum theorem, the impulse is equal to the change in momentum.F Δt = mvf - mv0impulse final initial momentum momentum

  19. Ex. 1 - A baseball (m = 0.14 kg) has an initial velocity of v0 = -38 m/s as it approaches a bat. The ball leaves the bat with a velocity of vf = +58 m/s. (a) Determine the impulse applied to the ball by the bat. (b) If the time of contact is Δt = 1.6 x 10-3 s, find the average force exerted on the ball by the bat.

  20. This is the principle of conservation of linear momentum.The total linear momentum of an isolated system remains constant.(mvf1+ mvf2) = (mv01+ mv02)or: Pf = P0

  21. Ex. 5 - A freight train is being assembled in a switching yard. Car 1 has a mass of m1 = 65 x103 kg and moves with a velocity of v01 = +0.80 m/s. Car 2, with a mass of m2 = 92 x 103 kg and a velocity of v02 = +1.2 m/s, overtakes car 1 and couples to it. Find the common velocity vf of the two cars after they become coupled.

  22. Ex. 7 - When a gun fires a blank, is the recoil greater than, the same as, or less than when the gun fires a standard bullet?

  23. An elastic collision is one in which the total kinetic energy of the system after the collision is equal to the total kinetic energy before the collision.K.E. is conserved in the collision.

  24. An inelastic collision is one in which the total kinetic energy of the system is not the same before and after the collision; if the objects stick together after colliding, the collision is said to be completely inelastic. Kinetic energy is not conserved.The coupling boxcars is an example of an inelastic collision.

  25. Ex. 9 - A ballistic pendulum consists of a block of wood (mass m2 = 2.50 kg) suspended by a wire. A bullet (mass m1 = 0.0100 kg) is fired with a speed v01. Just after the bullet collides with it, the block (now containing the bullet) has a speed vf and then swings to a maximum height of 0.650 m above the initial position. Find the speed of the bullet.

  26. In an isolated system momentum is conserved, Pf = P0. Remember that momentum is a vector quantity; when a collision in two dimensions occurs the x and y components are conserved separately.

  27. CH 8

  28. The angle through which a rigid body rotates about a fixed axis is called the angular displacement.

  29. Angular velocity is the angular displacement divided by elapsed time.w = Dq / Dt

  30. The unit is radians per second. rad/s

  31. Example 3. A gymnast on a high bar swings through two revolutions in time of 1.90 s. Find the average angular velocity (in rad/s) of the gymnast.

  32. Angular acceleration a is the rate of change of angular velocity.a = Dw / Dt

  33. Example 4. A jet engine’s turbine fan blades are rotating with an angular velocity of -110 rad/s. As the plane takes off, the angular velocity of the blades reaches -330 rad/s in a time of 14 s. Find the angular acceleration.

  34. The equations for rotational dynamics are similar to those for linear motion.w = w0 + at

  35. = w0t + ½ at2w2 =w02+ 2aq

  36. The tangential velocity vT is the speed in m/s around the arc. The magnitude is called the tangential speed.vT = rw

  37. The centripetal acceleration formula is ac = vT2/r. This can be expressed in terms of angular speed since vT = rw.

  38. ac = vT2/r becomes ac = (rw)2/rac = rw2(w is rad/s)

  39. When objects roll there is a relationship between the angular speed of the object and the linear speed at which the object moves forward.

  40. Linear speed is equal to tangential speed.v = rwIt follows that linear acceleration is equal to tangential acceleration.a = ra

  41. Right-Hand Rule. When the fingers of your right hand encircle the axis of rotation, and your fingers point in the direction of the rotation, your extended thumb points in the direction of the angular velocity vector.

  42. The direction of the angular acceleration vector is found the same way. The direction is determined by the change in angular velocity.

  43. If the angular velocity is increasing, the angular acceleration vector points in the same direction as the angular velocity.

  44. If the angular velocity is decreasing, the angular acceleration vector points in the opposite direction as the angular velocity.

  45. CH 9

  46. Torque Ƭ is the magnitude of the force multiplied by the lever arm. Ƭ = Fl

  47. ∑Fx = 0 and ∑Fy = 0 ∑Ƭ = 0The above must be true for all equilibrium conditions.

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