'Anhydrous salt' presentation slideshows

Unit 6: The Mathematics of Chemical Formulas

m. v. MOL. p. Chemistry. Unit 6: The Mathematics of Chemical Formulas. SO 3. Na 2 CO 3 . 10 H 2 O. Cu(OH) 2. 2. 1. 4. 2. 6. 3. 200. 100. 2 (6.02 x 10 23 ). 6.02 x 10 23. 18.0 g. 2.0 g. 16.0 g. molar mass :. the mass of one mole of a substance. (207.2 g). Pb :. Pb O 2.

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Unit 6: The Mathematics of Chemical Formulas

m. v. MOL. p. Chemistry. Unit 6: The Mathematics of Chemical Formulas. SO 3. Na 2 CO 3 . 10 H 2 O. Cu(OH) 2. 2. 1. 4. 2. 6. 3. 200. 100. 2 (6.02 x 10 23 ). 6.02 x 10 23. 18.0 g. 2.0 g. 16.0 g. molar mass :. the mass of one mole of a substance. (207.2 g). Pb :. Pb O 2.

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Unit 6: The Mathematics of Chemical Formulas

m. v. MOL. p. Outline. 6.02 EXP 23. Chemistry. Unit 6: The Mathematics of Chemical Formulas. SO 3. Na 2 CO 3 . 10 H 2 O. Cu(OH) 2. 2. 1. 4. 2. 6. 3. 200. 100. 2 (6.02 x 10 23 ). 6.02 x 10 23. 18.0 g. 2.0 g. 16.0 g. molar mass :. the mass of one mole of a substance.

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Empirical Formulas

Empirical Formulas. Percent Composition. Used to describe the composition by mass of various substances. Give individual percentage by mass of each element in a compound. Percentage is always. Practice.

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CHEM 1031

CHEM 1031. DETERMINATION OF THE FORMULA OF A HYDRATE. PURPOSE AND GOALS. DETERMINE THE NUMBER OF MOLES OF WATER IN AN UNKNOWN HYDRATE. PRINCIPLES. INORGANIC SALTS ANHYDROUS CONDITIONS HYDRATE-WATER MOLECULES BOUND. WATER MECHANICALLY TRAPPED CHEMICALLY BOUND.

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CHEM 1031

CHEM 1031. DETERMINATION OF THE FORMULA OF A HYDRATE. PURPOSE AND GOALS. DETERMINE THE NUMBER OF MOLES OF WATER IN AN UNKNOWN HYDRATE. PRINCIPLES. INORGANIC SALTS ANHYDROUS CONDITIONS HYDRATE-WATER MOLECULES BOUND. WATER MECHANICALLY TRAPPED CHEMICALLY BOUND.

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Waters of Hydration

Waters of Hydration. Purpose:. Determine the formula of a hydrate from experimental data. Failure to wear EYE safety GOGGLES. Hydrate = chemical with water molecules loosely bonded to it. Anhydrous salt (removing water from a Hydrate) Waters of hydration.

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Water of crystallisation calculations

Water of crystallisation calculations. A 0.970 g sample of a hydrated copper (II) salt, CuX 2 .6H 2 O was heated to give 0.538 g of the anhydrous salt. What is X?

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Water of crystallisation calculations

Water of crystallisation calculations. A 0.970 g sample of a hydrated copper (II) salt, CuX 2 .6H 2 O was heated to give 0.538 g of the anhydrous salt. What is X?

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Hydrate Lab Answers

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Laws and Percent Composition

Laws and Percent Composition. Law of Definite Proportions, 1797. Definition: States that in samples of any chemical compound, the masses of the elements are always in the same proportions Created by Joseph Proust Also called the Law of Constant Composition

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