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V ｘ

I=0 で測定するので Rx での電圧降下はなし、 よって、　 Vx=Ex. 変位法による測定. 零位法による測定. V ｘ. V ｘ =Ex-R ＊ I わずかに電流が流れるため、センサ内部の抵抗で電圧降下が発生 センサの出した電圧 Ex と 計測できる電圧 V ｘは異なってしまう. なぜ、零位法の方が精度良く測定できるのか？.

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V ｘ

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  1. I=0で測定するので Rxでの電圧降下はなし、 よって、　Vx=Ex 変位法による測定 零位法による測定 Vｘ Vｘ=Ex-R＊I わずかに電流が流れるため、センサ内部の抵抗で電圧降下が発生 センサの出した電圧Exと 計測できる電圧Vｘは異なってしまう なぜ、零位法の方が精度良く測定できるのか？

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