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CS 121 – Quiz 2

CS 121 – Quiz 2. Questions 4 and 5. Question 4. a) The arctangent function in Maple is arctan. b) To find the viewing angle, evaluate the given function θ(x) at the given point. Maple will give an exact answer, so you will have to approximate this to 10 decimal places.

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CS 121 – Quiz 2

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  1. CS 121 – Quiz 2 Questions 4 and 5

  2. Question 4 a) The arctangent function in Maple is arctan. b) To find the viewing angle, evaluate the given function θ(x) at the given point. Maple will give an exact answer, so you will have to approximate this to 10 decimal places. c) We are given that the first row is a feet from the screen and each row is b feet apart. We can then define the distance x for a certain row r by assigning x := a + b  (r – 1)

  3. We can then evaluate θ(x), which will give us a function of r. We can then plot this, and estimate the value of r at the maximum. We can check this by assigning nearby values to r, evaluating θ, and choosing the value that truly is the maximum. • Use the value from plugging in the r from part c into θ. • New measurements for the screen are given, with the screen being f feet tall and g feet off of the ground.

  4. We can redefine θ to bearctan((f + g) ÷ x) – arctan(g ÷ x) and solve similarly to part b. • Similar to part c, using the new θ. • Similar to part d, using the new θ.

  5. Question 5 • We are given Ti, Ta, t and T(t). We can plug these in and solve for k. • Divide 1 by k to get T1. • Use the same Ti and Ta, the given T(t) and the value of k we calculated. We can plug these in and solve for t. • Use the same Ti and Ta, the value of k we calculated, and t = 3  T1 (might not be 3, depending on your problem). We can plug these in, solve for T(t), and divide (T(t) - Ti)÷ (Ta - Ti).

  6. Similar to part a. • Similar to part d. • Similar to part b. • Similar to part c.

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