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Achieve success in the C1000-112 exam with our comprehensive guide on Quantum Computation using Qiskit v0.2X Developer 2

The C1000-112 Fundamentals of Quantum Computation Using Qiskit v0.2X Developer 2023 exam is a comprehensive test designed to assess the knowledge and proficiency of individuals in the field of quantum computing. The exam is designed to evaluate an individual's ability to understand and apply quantum computing principles using Qiskit v0.2X Developer 2023. Quantum computing is an emerging field of study that deals with the development of quantum computers and their applications. <br>https://www.certsgrade.com/pdf/c_bw4h_211/

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Achieve success in the C1000-112 exam with our comprehensive guide on Quantum Computation using Qiskit v0.2X Developer 2

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  1. C E R T S GR A DE High Grade and Valuable Preparation Stuff High Grade and Valuable Preparation Stuff IBM C1000-112 Fundamentals of Quantum Computation Using Qiskit v0.2X Developer Questions And Answers PDF Format: For More Information – Visit link below: https://www.certsgrade.com/ Version = Version = Product Visit us athttps://www.certsgrade.com/pdf/c1000-112/

  2. Latest Version: 6.0 Question: 1 S-gate is a Qiskit phase gate with what value of the phase parameter? Response: A.π/8 B.π/4 C.π D.π/2 Answer: D Question: 2 Which two options would place a barrier across all qubits to the QuantumCircuit below? qc = QuantumCircuit(3,3) Response: A.qc.barrier(qc) B.qc.barrier([0,1,2]) C.qc.barrier() D.qc.barrier(3) E.qc.barrier_all() Answer: B,C Question: 3 Which code fragment would yield an operator that represents a single-qubit X gate? Response: A.op = Operator.Xop(0) B.qc = QuantumCircuit(1) C.qc.x(0) D.op = Operator(qc) E.op = Operator([[0,1]]) F.op = Operator([[1,0,0,1]]) Answer: B Visit us athttps://www.certsgrade.com/pdf/c1000-112/

  3. Question: 4 What would be the fidelity result(s) for these two operators, which differ only by global phase? op_a = Operator(XGate()) op_b = numpy.exp(1j * 0.5) * Operator(XGate()) Response: A.state_fidelity() of 1.0 B.state_fidelity() and average_gate_fidelity() of 1.0 C.average_gate_fidelity() and process_fidelity() of 1.0 D.state_fidelity(), average_gate_fidelity() and process_fidelity() of 1.0 Answer: C Question: 5 Which three simulators are available in BasicAer? Response: A.qasm_simulator B.basic_qasm_simulator C.statevector_simulator D.unitary_simulator E.quantum_simulator F.quantum_circuit_simulator Answer: A,C,D Question: 6 Which code fragment will produce a maximally entangled, or Bell, state? Response: A.bell = QuantumCircuit(2) bell.h(0) bell.x(1) bell.cx(0, 1) B.bell = QuantumCircuit(2) bell.cx(0, 1) bell.h(0) bell.x(1) Visit us athttps://www.certsgrade.com/pdf/c1000-112/

  4. C.bell = QuantumCircuit(2) bell.h(0) bell.x(1) bell.cz(0, 1) D.bell = QuantumCircuit(2) bell.h(0) bell.h(0) Answer: A Question: 7 Which line of code would assign a statevector simulator object to the variable backend? Response: A.backend = BasicAer.StatevectorSimulatorPy() B.backend = BasicAer.get_backend('statevector_simulator') C.backend = BasicAer.StatevectorSimulatorPy().name() D.backend = BasicAer.get_back('statevector_simulator') Answer: B Question: 8 Which statement will create a quantum circuit with four quantum bits and four classical bits? Response: A.QuantumCircuit(4, 4) B.QuantumCircuit(4) C.QuantumCircuit(QuantumRegister(4, 'qr0'), QuantumRegister(4, 'cr1')) D.QuantumCircuit([4, 4]) Answer: A Question: 9 Which code fragment will produce a multi-qubit gate other than a CNOT? Response: A.qc.cx(0,1) B.qc.cnot(0,1) C.qc.mct([0],1) Visit us athttps://www.certsgrade.com/pdf/c1000-112/

  5. D.qc.cz(0,1) Answer: D Visit us athttps://www.certsgrade.com/pdf/c1000-112/

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