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Tips on cracking Aptitude Questions on Age

Tips on cracking Aptitude Questions on Age [ https://learningpundits.com/module-view/63-ages/1-tips-on-ages/]. <br><br>LearningPundits helps Job Seekers make great CVs [ https://learningpundits.com/module-view/1-cv-preparation-for-freshers/1-cv-writing-tips-for-freshers/ ] , master English Grammar and Vocabulary [ https://learningpundits.com/course/4-english-grammar/ ] , ace Aptitude Tests [ https://learningpundits.com/course/11-mathematical-aptitude/ ], speak fluently in a Group Discussion [ https://learningpundits.com/module-view/6-group-discussion-questions/1-tips-for-speaking-in-a-group-discussion/ ] and perform well in Interviews [ https://learningpundits.com/course/2-personal-interview/ ] We also conduct weekly online contests on Aptitude and English [ https://learningpundits.com/contest ]. We also allow Job Seekers to apply for Jobs [ https://learningpundits.com/applyForJobs ]

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Tips on cracking Aptitude Questions on Age

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  1. 4 TIPS on cracking Aptitude Questions related to Age

  2. Tip#1: Choose only one variable to solve the problem. Question: Mindy’s current age is 3 times that of her daughter, Cindy. 4 years ago, Mindy’s age was 4 times that of her daughter, what will be Cindy’s age 5 years from now? Solution: Let Cindy’s current age be x. Then Mindy’s age is 3x. According to the question, 3x-4=4(x-4) Or, 3x-4=4x-16 Or, x=12. Thus, 5 years from now, Cindy’s age will be 12+5=17years.

  3. Tip #2: If the question contains ages at different points of time, choose the present age as ‘x’. • Question: Ten years from now, Rachel will be three times older than she is today. What is her current age? • Solution: • Let current age be x. • Then, according to the question, • x+10= 3x • 2x=10 • x=5

  4. Tip #3: In questions containing the ages of different people, consider the age of the youngest person to be ‘x’. • Question: John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years time, the sum of their ages will be 58. How old is John now? • Solution: • Let Alice’s current age be x. Then John’s age=2x and their father’s age is 10x. • According to the question, • (x+2)+(2x+2)+(10x+2)=58 • 13x=58-6 • x=4 • John’s present age=10x4=40 years.

  5. Tip #4: Read the question very carefully. The phrase ‘n time more than’ needs to be understood correctly. • Question: A’s age is twice greater than B’s. If the sum of their ages is 24, what is A’s age? • Solution: • Let B’s age be x. • Then A’s age= x + 2x= 3x (and not 2x) • Now, x+3x= 24 • Or, x= 6. • A’s age is 3x= 18 years • Question: Mary is three times as old as her son. In 12 years, Mary's age will be one year less than twice her son's age. How old is each now? • Solution: • Let the son’s age be x. Then Mary’s age= 3x. • Given, • 3x+12= 2(x+12) – 1 • 3x+12= 2x+ 23 • x=11 • Mary’s age= 33 years, Son’s age= 11 years.

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