Exercise 1: Basic Design Criteria

1. Exercise 1: Basic Design Criteria 1) Route 17 is a minor arterial and it has a design ADT of 4000. Assume rolling terrain. Determine the following information:

2. Exercise 1: Basic Design Criteria 2) You are realigning a portion of I-44, assuming rolling terrain, determine the following: 70 mph D-61 3 625 ft 250 ft dual 6:1, 4 ft 4% 150-220 What type of R/W access do you think I-44 requires? Fully Controlled

3. Exercise 1: Basic Design Criteria 3) You are designing a 4-lane principal arterial, find the following design criteria. This is an urban setting. 40 mph 5% 14 60-70 10 10 or 12 275 ft 0.04 or 4% None Required Yes 12 ft, none 5

4. Exercise 2: Horizontal Alignment, Simple and Spiral Curves Given Information to fix substandard curve: • Road is principal arterial with ADT=1500 • Back bearing is N 85^ 49’ 13” E • Ahead bearing is S 56^ 39’ 24” E • D= 37^ 31’ 23” (RT) • Design curve, find L & T • If the PC station starts at 15+63.34, what are the PI & PT stations for the curve you designed? • When does MoDOT require spiral curves? L = 750 ft & T = 389.00 ft PI = 1563.34 + 389.00 = 1952.34 PI sta = 19+52.34 PT = 1563.34 + 750 = 2313.34 PT sta = 23+13.34 When degree of curve > 2 V >50 mph ADT > 400

5. Exercise 2: Horizontal Alignment, Simple and Spiral Curves • Design a spiral curve based on MoDOT Design Criteria • What’s the transition length, Ls? • If the curve is 617.88 ft long, what’s the overall length of the SCS? • If the station at the SC point is 16+50.42, what are the stations at TS and ST points? Ls=192 617.88 +192+192=1001.88 ft TS= 1650.42 – 192 = 1458.42, so TS station = 14+58.42 CS = 1650.42 + 617.88 = 2268.30, so CS station = 22+68.30 ST = 2268.30 + 192 = 2460.30, so ST station = 24+60.30

6. Exercise 3: Horizontal Alignment, Simple and Spiral Curves Given information to design a temporary bypass: • Minor arterial with ADT = 1500 • 20 ft requirement between the EOP of main line and EOP of temporary bypass • d = 500 ft in length on each end of bypass • Find D, R, and L for this reverse curve • If the first PC station on the bypass starts at 20+00, what are the stations for the PRC and PT of the first reverse curve you designed? D = 10^ 3’ 29” (10.058^), R = 1431.47 ft, L = 251.29 ft PRC = 2000.00 + 251.29 = 2251.29, so PRC station = 22+51.29 PT = 2251.29 + 251.29 = 2502.58, so PT station = 25+02.58

7. Exercise 4: Horizontal Alignment, Superelevation Fix the substandard superelevation transitions on the following project without re-aligning the curve: • Principal arterial with ADT = 22940, • NC(%) = 2, rural flat terrain • Existing Curve Data PC station = 388+72.21 D (degree of curve) = 3 PT station = 394+42.77 L = 570.56 ft PI station = 391+60.46 T = 288.25 ft • Find the SE rate and runoff length, specify the standard plan used Standard Drawing 203.21 pg 3/5 Runoff length, L = 356 ft

8. Exercise 4: Horizontal Alignment, Superelevation Fix the substandard superelevation transitions on the following project without re-aligning the curve: • Principal arterial with ADT = 22940, rural setting, NC(%) = 2 • Existing Curve Data PC station = 388+72.21 D (degree of curve) = 3 PT station = 394+42.77 L = 570.56 ft PI station = 391+60.46 T = 288.25 ft • Calculate the superelevation transition points.

9. Exercise 5: Horizontal Alignment, Horizontal Sight Distance Check for horizontal sight distance: • 2-lane minor arterial with ADT = 1890, rural setting on a rolling terrain, assume lane width = 12’ • Existing Curve Data PC station = 0+00 D = 29^ 30’ 6” (RT) D = 4^46’29” PT station = 6+17.88 L = 570.56 ft PI station = 3+15.65 T = 288.25 ft • Find the SSD for a sight of obstruction of 25 ft • Determine the distance of obstruction M based on Figure 4-04.2 & 4-04.3 SSD = 489.49 ft Round to 490 ft according to Fig. 4-01.1 M = 23.55 ft

10. Exercise 6: Vertical Alignment Design a crest curve that will meet MoDOT standards based on the given information: • Road is principal arterial with ADT=19,800 on a rolling terrain • Divided highway • Plus grade = 1.03% • Minus grade = 2.99% • PI station = 683+50.00 with elevation = 676.99 ft • Based on the length of curve designed, calculate SSD, PSD and K value if appropriate • What is the station at the VPC and VPT? • Calculate the high point of the curve For “my” L 1210 ft, K = 301 and SSD = 650 ft VPC station = 677 + 45 VPC elevation = 670.76 ft VPT station = 689 + 55 VPT elevation = 658.90 ft Xm = 310.02 ft HP station = 680+55.02; HP elevation = 675.55 ft

11. Exercise 7: At-Grade Intersections (Handout) Given: Find:

12. Comprehensive Lab: Horizontal, Vertical Alignment and Sight Distance Given:

13. Comprehensive Lab: Horizontal, Vertical Alignment and Sight Distance 1. Find L, R, and T for each curve 2. Find PC, PI, and PT stationing for each curve

14. Comprehensive Lab: Horizontal, Vertical Alignment and Sight Distance 3. Find superelevation transition points

15. Comprehensive Lab: Horizontal, Vertical Alignment and Sight Distance 4. Find VPI and VPT stationing and elevations for e/vertical curve

16. Comprehensive Lab: Horizontal, Vertical Alignment and Sight Distance 5. Calculate the low and/or high point for each vertical curve