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Momentum

Momentum. Recall: All objects have inertia (the resistance to a change in motion) When the object is in motion, we refer to the inertia as momentum The momentum of an object is equal to: mass × velocity If the direction of the object is not important, we can use: mass × speed. Momentum.

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Momentum

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  1. Momentum • Recall: All objects have inertia (the resistance to a change in motion) • When the object is in motion, we refer to the inertia as momentum • The momentum of an object is equal to: mass × velocity • If the direction of the object is not important, we can use:mass × speed

  2. Momentum ρ = momentum m = mass v = velocity or speed (Kgm/s) p = mv (Kg) (m/s)

  3. Momentum 1. A car with a mass of 1500 kg is traveling west at 60 m/s. What is the car’s momentum? ρ = m x v ρ = 1500 kg x 60 m/s ρ = 90,000 kgm/s west

  4. Momentum 2. A horse with a mass of 400 kg is traveling at 12 m/s. What is the horse’s momentum? Volunteer?

  5. Momentum 3. A man with a mass of 90 kg is traveling at 3 m/s. What is the man’s momentum? Volunteer?

  6. Law of Conservation of Momentum Newton’s 1st Law of Motion tells us that the velocity of an object remains the same without an outside force. The mass of the object also remains the same. Therefore . . . The momentum of a system remains unchanged if no external forces are present.

  7. Law of Conservation of Momentum A bullet is shot from a gun. What do we know about the force exerted on the bullet and the gun?

  8. Law of Conservation of Momentum A bullet is shot from a gun. Is the momentum conserved for the bullet? Why or why not?

  9. Law of Conservation of Momentum A bullet is shot from a gun. Is the momentum conserved for the gun? Why or why not?

  10. Law of Conservation of Momentum A bullet is shot from a gun. Is the momentum conserved for the gun-bullet system? Why or why not?

  11. Law of Conservation of Momentum mgun = 5 Kg mbullet = 0.010 Kg vbullet = 250 m/s vgun = ? We can calculate the recoil velocity of the gun using the law of conservation of momentum.

  12. m1 x v1 m2 0.01 Kg x 250 m/s 5 Kg Law of Conservation of Momentum mbullet = 0.010 Kg vbullet = 250 m/s m1 v1 mgun = 5 Kg vgun = ? m2 v2 m1 x v1 = m2 x v2 v2 = v2 = v2 = 0.5 m/s

  13. Law of Conservation of Momentum m1 = v1 = m1 v1 m2 = m2 v2 v2 = A 5 kg fish swimming at 2 m/s swallows an absent minded 1 kg fish swimming toward it at a velocity that brings both fish to a halt immediately after lunch. What is the velocity of the smaller fish before lunch? Volunteer?

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