1 / 18

Geo CP Day 24 > SWBAT state the midpoint and angle bisector theorem.

Geo CP Day 24 > SWBAT state the midpoint and angle bisector theorem. > SWBAT use these theorems in proofs. > SWBAT show perfection in doing basic proofs not involving midpoint and angle bisector theorems.

addo
Download Presentation

Geo CP Day 24 > SWBAT state the midpoint and angle bisector theorem.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Geo CP Day 24 > SWBAT state the midpoint and angle bisector theorem. >SWBAT use these theorems in proofs. > SWBAT show perfection in doing basic proofs not involving midpoint and angle bisector theorems. Hmwk: Pg. 49 Self-Test 1 All; pg. 45: Class Ex 1-9 All; Study Wednesday and Thursday power points to be ready for your Quiz Friday

  2. 4 + 2y +5 = 8x + 2 Substitution Geo CP Day 24 3x + 5 = 8x + 2 Given 3x = 4 + 2y Given

  3. 3x + 5 = 4 Substitution or Transitivity Geo CP Day 24 3x + 5 = 8x + 2 Given 8x + 2 = 4 Given

  4. Z + W = 8x + 2 Substitution or Transitivity Geo CP Day 24 3x + 5 = 8x + 2 Given 3x + 5 = Z + W Given

  5. 3x + 5 = W + 2 Substitution Geo CP Day 24 3x + 5 = 8x + 2 Given 8x = W Given

  6. ? 8x + 2 = 3x + 5 Symmetric prop = Geo CP Day 24 3x + 5 = 8x + 2 Given

  7. 5 = 5x + 2 Subtra prop = Geo CP Day 24 3x + 5 = 8x + 2 Given 3x = 3x Given

  8. m<1 = m<3 Trans prop = Geo CP Day 24 m<1 = m< 2 Given m<2 = m<3 Given

  9. m<1+m<2 = m<2+m<3 Addit prop = Geo CP Day 24 m<1 = m< 2 Given m<2 = m<3 Given

  10. AX + XB = DY Substitution Geo CP Day 24 AX + XB = DZ + ZY Given DZ + ZY = DY Given

  11. A M B Segment Addition p1 + p2 = w • M Btwn A,B  • AM + MB = AB Segment Postulates and Theorems

  12. A 1 M X 2 B Def < Bisector • m<1 = m<2 • XM Bisects <AXB  • ½ m<AXB = m<1 or… Angle Postulates and Theorems < Bisector Theorem

  13. A M B • M Midpt A,B  • AM = MB • or • ½ AB = AM or MB Def. of Midpt Segment Postulates and Theorems Midpt Theorem

  14. M B A 1 2 X Def. of a Supplementary Angles m<1 + m<2 = 180 m<AXM + m<MXB = 180

  15. Given • m<1 = m<2 • m<3 = m<4 2. m<1 + m<3 = m<2 + m<4 Add prop = Given: m<1 = m<2; m<3 = m<4 #11 Prove: m<SRT = m<STR 3. m<1 + m<3 = m<SRT m<2 + m<4 = m<STR Angle add post 4. m<SRT = m<STR Subtit prop =

  16. Given • m<SRT = m<STR 2. m<SRT = M<3 + m<1 m<SRT = M<4 + m<2 Angle Add Post 3. m<3 + m<1 = m<4 + m<2 Substitution Given: m<SRT = m<STR; m<3 = m<4 #14 Prove: m<1 = m<2 4. m<3 = m<4 Given 5. m<1 = m<2 Subtr prop =

  17. 1. DW = ON 1. Given 2. DW = DO + OW ON = ____ + ____ 2. Seg Addition OW WN Given: DW = ON #9 Prove: DO = WN 3. _______________ 3. Substitution DO + OW = OW + WN Reflex prop = 4. OW = OW 4. ___________ DO = WN Subtra prop = 5. _____________ 5. ___________

  18. 1. RP = TQ 1. Given PS = QS 2. RP + PS = TQ + QS 2. Add. Prop = Given: RP = TQ & PS = QS #12 Prove: RS = QS 3. RP + PS = RS 3. Seg. Add. = 4. RS = TQ + QS 4. Substitution 5. _____________ 5. ___________

More Related