1 / 38

Queues

Queues. Linear list. One end is called front . Other end is called rear . Additions are done at the rear only. Removals are made from the front only. Bus Stop. Bus Stop Queue. front. rear. rear. rear. rear. rear. Bus Stop. Bus Stop Queue. front. rear. rear. rear.

adonai
Download Presentation

Queues

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Queues • Linear list. • One end is called front. • Other end is called rear. • Additions are done at the rear only. • Removals are made from the front only.

  2. Bus Stop Bus Stop Queue front rear rear rear rear rear

  3. Bus Stop Bus Stop Queue front rear rear rear

  4. Bus Stop Bus Stop Queue front rear rear

  5. Bus Stop Bus Stop Queue front rear rear

  6. Revisit Of Stack Applications • Applications in which the stack cannot be replaced with a queue. • Parentheses matching. • Towers of Hanoi. • Switchbox routing. • Method invocation and return. • Try-catch-throw implementation. • Application in which the stack may be replaced with a queue. • Rat in a maze. • Results in finding shortest path to exit.

  7. Wire Routing

  8. start pin end pin Lee’s Wire Router Label all reachable squares 1 unit from start.

  9. start pin end pin Lee’s Wire Router 1 1 Label all reachable unlabeled squares 2 units from start.

  10. start pin end pin Lee’s Wire Router 2 2 1 1 2 2 2 Label all reachable unlabeled squares 3 units from start.

  11. start pin end pin Lee’s Wire Router 3 3 2 2 1 1 2 2 2 3 3 Label all reachable unlabeled squares 4 units from start.

  12. start pin end pin Lee’s Wire Router 4 3 3 2 2 1 1 2 2 2 3 4 3 4 4 4 Label all reachable unlabeled squares 5 units from start.

  13. start pin end pin Lee’s Wire Router 5 4 5 3 3 2 2 1 1 2 2 2 3 4 3 4 5 4 4 5 5 5 Label all reachable unlabeled squares 6 units from start.

  14. start pin end pin Lee’s Wire Router 6 5 6 4 5 3 3 2 2 1 1 2 2 2 6 3 4 3 4 5 6 4 4 5 6 5 6 5 6 6 End pin reached. Traceback.

  15. start pin end pin 1 2 3 4 Lee’s Wire Router 6 5 6 4 5 3 3 2 2 1 1 2 2 2 6 3 4 3 4 5 5 6 4 4 5 6 5 6 5 6 6 End pin reached. Traceback.

  16. Queue Operations • IsFullQ … return true iff queue is full • IsEmptyQ … return true iff queue is empty • AddQ … add an element at the rear of the queue • DeleteQ … delete and return the front element of the queue

  17. Queue in an Array • Use a 1D array to represent a queue. • Suppose queue elements are stored with the front element in queue[0], the next in queue[1], and so on.

  18. a b c d e 0 1 2 3 4 5 6 Queue in an Array • DeleteQ() => delete queue[0] • O(queue size) time • AddQ(x) => if there is capacity, add at right end • O(1) time

  19. O(1) AddQ and DeleteQ • to perform each opertion in O(1) time (excluding array doubling), we use a circular representation.

  20. queue[] [2] [3] [1] [4] [0] [5] Circular Array • Use a 1D array queue. • Circular view of array.

  21. [2] [3] A B C [1] [4] [0] [5] Circular Array • Possible configuration with 3 elements.

  22. [2] [3] C [1] [4] B A [0] [5] Circular Array • Another possible configuration with 3 elements.

  23. [2] [3] [2] [3] A B rear rear front front C C [1] [4] [1] [4] B A [0] [5] [0] [5] Circular Array • Use integer variables front and rear. • front is one position counterclockwise from first element • rear gives position of last element

  24. [2] [3] A B rear front C [1] [4] [0] [5] Add An Element • Move rear one clockwise.

  25. [2] [3] A B front C [1] [4] [0] [5] rear Add An Element • Move rear one clockwise. • Then put into queue[rear]. D

  26. [2] [3] A B rear front C [1] [4] [0] [5] Delete An Element • Move front one clockwise.

  27. [2] [3] front A B rear C [1] [4] [0] [5] Delete An Element • Move front one clockwise. • Then extract from queue[front].

  28. [2] [3] A B rear front C [1] [4] [0] [5] Moving rear Clockwise • rear++; • if(rear = = capacity) rear = 0; • rear = (rear + 1) % capacity;

  29. [2] [3] rear front C [1] [4] B A [0] [5] Empty That Queue

  30. [2] [3] rear C [1] [4] B [0] [5] Empty That Queue front

  31. [2] [3] rear C [1] [4] [0] [5] Empty That Queue front

  32. [2] [3] rear [1] [4] [0] [5] Empty That Queue • When a series of removes causes the queue to become empty, front = rear. • When a queue is constructed, it is empty. • So initialize front = rear = 0. front

  33. [2] [3] rear front C [1] [4] B A [0] [5] A Full Tank Please

  34. [2] [3] rear front [1] [4] [0] [5] A Full Tank Please D C B A

  35. [2] [3] front [1] [4] [0] [5] A Full Tank Please rear D E C B A

  36. [2] [3] front [1] [4] [0] [5] A Full Tank Please D E C F B A rear • When a series of adds causes the queue to become full, front = rear. • So we cannot distinguish between a full queue and an empty queue!

  37. Ouch!!!!! • Remedies. • Don’t let the queue get full. • When the addition of an element will cause the queue to be full, increase array size. • This is what the text does. • Define a boolean variable lastOperationIsAddQ. • Following each AddQ set this variable to true. • Following each DeleteQ set to false. • Queue is empty iff (front == rear) && !lastOperationIsAddQ • Queue is full iff (front == rear) && lastOperationIsAddQ

  38. Ouch!!!!! • Remedies (continued). • Define an integer variable size. • Following each AddQ do size++. • Following each DeleteQ do size--. • Queue is empty iff (size == 0) • Queue is full iff (size == arrayLength) • Performance is slightly better when first strategy is used.

More Related