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Matlab Code. clear all; L=1E-3; Vd=100; Ts=50E-6; %IL=zeros(100,1); ILB_max=Vd*Ts/(8*L); N=2*ILB_max/0.01; i=1; while(i<N) IL(i)=0.01*i; i=i+1; end M=size(IL);. 初始值. 特徵曲線. figure(1); for j=1:2:9 D=0.1*j; ILB=D*Ts*(Vd-D*Vd)/(2*L); for i=1:1:M(2)
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Matlab Code clear all; L=1E-3; Vd=100; Ts=50E-6; %IL=zeros(100,1); ILB_max=Vd*Ts/(8*L); N=2*ILB_max/0.01; i=1; while(i<N) IL(i)=0.01*i; i=i+1; end M=size(IL); 初始值 特徵曲線 figure(1); for j=1:2:9 D=0.1*j; ILB=D*Ts*(Vd-D*Vd)/(2*L); for i=1:1:M(2) if (IL(i)>ILB) ratio(1,i)=D; ratio(2,i)=IL(i); else ratio(1,i)=D^2/(D^2+0.25*IL(i)/ILB_max); ratio(2,i)=IL(i); end end plot(ratio(2,:),ratio(1,:)); hold on; end 電感電流極限值 for i=1:1:100 Duty=i*0.01; ILB_matrix(1,i)=Duty*Ts/2/L*(Vd-Duty*Vd); ILB_matrix(2,i)=Duty; end plot(ILB_matrix(1,:),ILB_matrix(2,:)) hold off; grid on;
穩態特徵曲線 D=0.9 CCM D=0.7 DCM D=0.5 D=0.3 D=0.1 Io
Buck Converter Circuit Iload Duty
X-Y Curve Io
Steady State Curve 與計算結果有差異!!! Io Io
完成Duty=0.1, 0.3, 0.5, 0.7, 0.9 之特性曲線 用Matlab將曲線繪出在同一張圖上 將Psim所得之圖與Matlab計算之圖做比較,並分析可能不相等原因? 作業
Step-Down DC-DC Converter: Limits of Cont./Discont. Conduction (c) Boundary Curve (a) CCM DCM (b) CCM DCM combine (a) and (b) ,we can plot (c) BCM
[1] M.Sanz, A.Lazaro‚ “Improvement of Power Electronics Education with an Interactive Electronic Book based on MathCAD‚” IEEE Power Electronics Education‚ 2005. [2] Cristian Domnisoru‚ “Using MATHCAD in Teaching Power Engineering‚” IEEE trans On Education‚ VOL. 48‚NO.1‚ FEBRUARY 2005. [3] R. W. Larsen‚ “Introduction to MATHCAD‚” Englewood Cliffs‚ NJ: Prentice-Hall‚ 1999. [4] Mathcad User’s Guide‚ MathSoft‚ Cambridge‚MA‚ 2001. [5] Alan Felzer, “Introduction to MathCAD,” 2003 [6] ST AN1089 Application Note [7] Lai, J.-S.; Chen, D.‚ “Design consideration for power factor correction boost converter operating at the boundary of continuous conduction mode and discontinuous conduction mode.” in Proc. IEEE Appl. Power Electron. Conf, 7-11, Mar. 1993. pp.267 – 273 REFERENCES