1 / 65

Distribution of Sample Mean in Normal and Non-Normal Populations

Learn about the distribution of the sample mean in samples from normal populations and populations that are not normal. Understand the effect of sample size on the standard deviation of the distribution of the sample mean.

aebert
Download Presentation

Distribution of Sample Mean in Normal and Non-Normal Populations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chapter 8 Sampling Distributions

  2. Section 8.1 Distribution of the Sample Mean

  3. Objectives • Describe the distribution of the sample mean: samples from normal populations • Describe the distribution of the sample mean: samples from a population that is not normal

  4. Statistics such as are random variables since their value varies from sample to sample. As such, they have probability distributions associated with them. In this chapter we focus on the shape, center and spread of statistics such as .

  5. The sampling distribution of a statistic is a probability distribution for all possible values of the statistic computed from a sample of size n. The sampling distribution of the sample mean is the probability distribution of all possible values of the random variable computed from a sample of size n from a population with mean μ and standard deviation σ.

  6. Illustrating Sampling Distributions • Step 1: Obtain a simple random sample of size n.

  7. Illustrating Sampling Distributions • Step 1: Obtain a simple random sample of size n. • Step 2: Compute the sample mean.

  8. Illustrating Sampling Distributions • Step 1: Obtain a simple random sample of size n. • Step 2: Compute the sample mean. • Step 3: Assuming we are sampling from a finite population, repeat Steps 1 and 2 until all simple random samples of size n have been obtained.

  9. Given the following data: 2 3 5 6 7 8 9 11 14 16 17 18 19 22 24 30 Choose a SRS of size 6 Find the mean and standard deviation of your sample. We will then combine the class data on the board.

  10. Objective 1 • Describe the Distribution of the Sample Mean- Samples from Normal Populations

  11. Parallel Example 1: Sampling Distribution of the Sample Mean-Normal Population The weights of pennies minted after 1982 are approximately normally distributed with mean 2.46 grams and standard deviation 0.02 grams. Approximate the sampling distribution of the sample mean by obtaining 200 simple random samples of size n = 5 from this population.

  12. The data on the following slide represent the sample means for the 200 simple random samples of size n = 5. For example, the first sample of n = 5 had the following data: 2.493 2.466 2.473 2.492 2.471 Note: = 2.479 for this sample

  13. Sample Means for Samples of Size n =5

  14. The mean of the 200 sample means is 2.46, the same as the mean of the population. The standard deviation of the sample means is 0.0086, which is smaller than the standard deviation of the population. The next slide shows the histogram of the sample means.

  15. What role does n, the sample size, play in the standard deviation of the distribution of the sample mean?

  16. What role does n, the sample size, play in the standard deviation of the distribution of the sample mean? As the size of the sample gets larger, we do not expect as much spread in the sample means since larger observations will offset smaller observations.

  17. Parallel Example 2: The Impact of Sample Size on Sampling Variability • Approximate the sampling distribution of the sample mean by obtaining 200 simple random samples of size n = 20 from the population of weights of pennies minted after 1982 (μ = 2.46 grams and σ = 0.02 grams)

  18. The mean of the 200 sample means for n = 20 is still 2.46, but the standard deviation is now 0.0045 (0.0086 for n = 5). As expected, there is less variability in the distribution of the sample mean with n = 20 than with n = 5.

  19. The Mean and Standard Deviation of the Sampling Distribution of Suppose that a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ. The sampling distribution of will have mean and standard deviation . The standard deviation of the sampling distribution of is called the standard error of the mean and is denoted .

  20. Determine from the given parameters of the population and the sample size. • μ = 84 σ= 12 n = 30 • 12 • 5.477 • 84 • 15.336

  21. Determine from the given parameters of the population and the sample size. • μ = 84 σ= 12 n = 30 • 12 • 5.477 • 84 • 15.336

  22. Determine from the given parameters of the population and the sample size. • μ = 84 σ= 12 n = 30 • 12 • 5.477 • 15.336 • 2.191

  23. Determine from the given parameters of the population and the sample size. • μ = 84 σ= 12 n = 30 • 12 • 5.477 • 15.336 • 2.191

  24. The Shape of the Sampling Distribution of If X is Normal If a random variable X is normally distributed, the distribution of the sample mean is normally distributed.

  25. Parallel Example 3: Describing the Distribution of the Sample Mean The weights of pennies minted after 1982 are approximately normally distributed with mean 2.46 grams and standard deviation 0.02 grams. What is the probability that in a simple random sample of 10 pennies minted after 1982, we obtain a sample mean of at least 2.465 grams?

  26. Solution • is normally distributed with =2.46 and . • . • P(Z>0.79)=1-0.7852 =0.2148.

  27. IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. What is the probability a random sample of 20 people have a mean IQ score greater than 110? • 0.0014 • 0.7486 • 0.9986 • 0.2514

  28. IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. What is the probability a random sample of 20 people have a mean IQ score greater than 110? • 0.0014 • 0.7486 • 0.9986 • 0.2514

  29. Home sizes in Anytown, USA have a mean of 2400 square feet and a standard deviation of 450 square feet. What is the probability that a random sample of 50 homes in Anytown, USA has a mean square footage less than 2200 square feet? • 0.3300 • 0.9992 • 0.4761 • 0.0008

  30. Home sizes in Anytown, USA have a mean of 2400 square feet and a standard deviation of 450 square feet. What is the probability that a random sample of 50 homes in Anytown, USA has a mean square footage less than 2200 square feet? • 0.3300 • 0.9992 • 0.4761 • 0.0008

  31. Objective 2 • Describe the Distribution of the Sample Mean-Samples from a Population That is Not Normal

  32. Parallel Example 4: Sampling from a Population that is Not Normal The following table and histogram give the probability distribution for rolling a fair die: μ =3.5, σ = 1.708 Note that the population distribution is NOT normal

  33. Estimate the sampling distribution of by obtaining 200 simple random samples of size n=4 and calculating the sample mean for each of the 200 samples. Repeat for n = 10 and 30. Histograms of the sampling distribution of the sample mean for each sample size are given on the next slide.

  34. Key Points from Example 4 • The mean of the sampling distribution is equal to the mean of the parent population and the standard deviation of the sampling distribution of the sample mean is regardless of the sample size. • The Central Limit Theorem: the shape of the distribution of the sample mean becomes approximately normal as the sample size n increases, regardless of the shape of the population.

  35. Parallel Example 5: Using the Central Limit Theorem • Suppose that the mean time for an oil change at a “10-minute oil change joint” is 11.4 minutes with a standard deviation of 3.2 minutes. • If a random sample of n = 35 oil changes is selected, describe the sampling distribution of the sample mean. • (b) If a random sample of n = 35 oil changes is selected, what is the probability the mean oil change time is less than 11 minutes?

  36. Parallel Example 5: Using the Central Limit Theorem Suppose that the mean time for an oil change at a “10-minute oil change joint” is 11.4 minutes with a standard deviation of 3.2 minutes. If a random sample of n = 35 oil changes is selected, describe the sampling distribution of the sample mean. (b) If a random sample of n = 35 oil changes is selected, what is the probability the mean oil change time is less than 11 minutes? Solution: is approximately normally distributed with mean=11.4 and std. dev. = . • Solution: , P(Z<-0.74)=0.23.

  37. Section 8.2 Distribution of the Sample Proportion

  38. Objectives • Describe the sampling distribution of a sample proportion • Compute probabilities of a sample proportion

  39. Objective 1 • Describe the Sampling Distribution of a Sample Proportion

  40. Point Estimate of a Population Proportion Suppose that a random sample of size n is obtained from a population in which each individual either does or does not have a certain characteristic. The sample proportion, denoted (read “p-hat”) is given by where x is the number of individuals in the sample with the specified characteristic. The sample proportion is a statistic that estimates the population proportion, p.

  41. Parallel Example 1: Computing a Sample Proportion In a Quinnipiac University Poll conducted in May of 2008, 1,745 registered voters nationwide were asked whether they approved of the way George W. Bush is handling the economy. 349 responded “yes”. Obtain a point estimate for the proportion of registered voters who approve of the way George W. Bush is handling the economy.

  42. Parallel Example 1: Computing a Sample Proportion In a Quinnipiac University Poll conducted in May of 2008, 1,745 registered voters nationwide were asked whether they approved of the way George W. Bush is handling the economy. 349 responded “yes”. Obtain a point estimate for the proportion of registered voters who approve of the way George W. Bush is handling the economy. Solution:

  43. Parallel Example 2: Using Simulation to Describe the Distribution of the Sample Proportion According to a Time poll conducted in June of 2008, 42% of registered voters believed that gay and lesbian couples should be allowed to marry. Describe the sampling distribution of the sample proportion for samples of size n=10, 50, 100.

More Related