Unit 2

1. Unit 2 MAKE UP TEST CORRECTIONS TONIGHT AT 7PM ROOM CC-18 Justin Shulman, Ben Errera , Amanda Diedrick, Rob O’Connor, Owen Jean Jacques

2. Section 2-3, Problem Solving Using Inequalities • Objective: To solve word problems by using inequalities in one variable. • Do now: Without the book write the definition for Conjunction and Disjunction • Homework: • Pg 71 -1, 3, 4, 13, 15, • Self test 1 Page 72 1 – 7 ALL

3. Homework Questions????

4. Problem solving inequalities Problem Solution The problem asks for the least number of passengers needed to make the fare for each less than $7.50 Let n= the number of passengers Then n-20 = the number of passengers over 20 0.30(n-20)=the amount each passenger’s fare is reduced 9.50-0.30(n-20)= the reduced fare per passenger • A bus is to be chartered for the senior class trip. The basic fare is $9.50 per passenger. If more than 20 people go, everyone’s fare is reduced by $0.30 for each passengers over over this number. At least how many people must go to make the fare less than $7.50 per passenger.

5. Problem Solution continued. The reduced fair per passenger is less than $7.50 9.50-0.30(n-20)<$7.50 Solve Check Answer • A bus is to be chartered for the senior class trip. The basic fare is $9.50 per passenger. If more than 20 people go, everyone’s fare is reduced by $0.30 for each passengers over over this number. At least how many people must go to make the fare less than $7.50 per passenger.

6. Check Answer • 9.50-0.30(n-20)<$7.50

7. Certain phrases can be translated into mathematical terms Phrase Translation • X is at least a • X is no less than a • X is at most b • X is no greater than b • X is between a and b • X is between a and b, inclusive

8. Find all sets of 4 consecutive integers whose sum is between 10 and 20 • 10 < the sum <20 • 10< n+ (n+1) +(n+2) +(n+3)<20 • 10<4n+6<20 • 4 < 4n <14 • 1 < n < 14/4 • Interpret the results: since n is the integer, there are only two possible values for n : 2 and 3 . • {2,3,4,5} AND {3,4,5,6} • The problem asks for 4 consecutive integers; their sum must be greater than 10 and less than 20 • Let n = the first of these integers • Then the other three are • n+1,n+2,and n+3

9. Check Answer • {2,3,4,5} AND {3,4,5,6} • Is the sum between 10 and 20? • For {2,3,4,5}: 10 < 2+3+4+5<20 • 10<14<20 • For {3,4,5,6}: 10<3+4+5+6<20 • 10<18<20 To complete the check we must show that any other set of four consecutive integers will not satisfy the requirement. Eliminate the next greater set of four integers and next smaller integers.

10. In pairs work together to complete the following: • The Perez family has 100 more shares of stock B than of stock A. The current price per share of stock A is $18.50 and stock B is $24.75. At most how many shares of each do they have if the average price per share is greater than $22? • Find all the sets of five consecutive even integers whose sum is between 225 and 250

11. Word Problem Answer Solution Solve • The problem asks for the maximum number of shares of each stock. • Let a= number of shares of stock A. Then a+100 = number of shares of stock B. • 18.5a+24.75(a+100) • a+(a+100) >22

12. Solve 5 integers problem

13. Start in on your homework • Pg 71 -1, 3, 4, 13, 15, • Self test 1 Page 72 1 – 7 ALL