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How much heat is given off when an 869 g iron bar cools from 94 0 C to 5 0 C?. s of Fe = 0.444 J/g • 0 C. D t = t final – t initial = 5 0 C – 94 0 C = -89 0 C. q = ms D t. = 869 g x 0.444 J/g • 0 C x –89 0 C. = -34,000 J.
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How much heat is given off when an 869 g iron bar cools from 940C to 50C? s of Fe = 0.444 J/g •0C Dt = tfinal – tinitial = 50C – 940C = -890C q = msDt = 869 g x 0.444 J/g •0C x –890C = -34,000 J