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Archimedes’ Principle. An object immersed in a liquid has an upward buoyant force equal to the weight of the liquid displaced by the object. An object will float if the upward buoyant force is greater than the object’s weight. Archimedes 287 – 211 BC. (courtesy F. Remer).
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Archimedes’ Principle • An object immersed in a liquid has an upward buoyant force equal to the weight of the liquid displaced by the object. • An object will float if the upward buoyant force is greater than the object’s weight. Archimedes 287 – 211 BC (courtesy F. Remer)
Archimedes’ Principle • ‘Square’ bubble of gas in a tank of water (courtesy F. Remer)
Archimedes’ Principle • Water pressure in tank increases with depth • p = pressure • h = depth p h (courtesy F. Remer)
Archimedes’ Principle • Horizontal Pressure Differences Balance (courtesy F. Remer)
Archimedes’ Principle • Force on bottom of ‘bubble’ Fbottom
Archimedes’ Principle • Force on top of ‘bubble’ Ftop Fbottom (courtesy F. Remer)
Archimedes’ Principle • Buoyancy Force FB Ftop Fbottom (courtesy F. Remer)
Archimedes’ Principle • Pressure Difference Between Top & Bottom • Negative by convention ptop pbottom (courtesy F. Remer)
Archimedes’ Principle • Combine Equations B ptop pbottom Note: Density (ρ) = density of liquid Volume = displaced volume of liquid = volume of object (courtesy F. Remer)
Archimedes Principle • The net force on the object is thus the difference between the object’s weight and the buoyancy force of the displaced fluid. • If the buoyancy of an object exceeds its weight, it tends to rise. An object whose weight exceeds its buoyancy tends to sink. Weight of object Buoyant Force of displaced fluid
Archimedes’ Principle Archimedes 287 – 211 BC Cartoon here?? At the moment of Archimedes’ famous discovery.
Example • What is the buoyancy in seawater of a piece of wood that weighs 10,000 N & measures 3m x 1m x 2m? • The weight of wood = 10,000 N • The volume of wood = 3m x 2m x 1m= 6 m3 • The corresponding weight of an equal volume of seawater: 6 m3 x 10300N/m3 = 61,800N weight of water displaced = upward force = 61,800N weight of wood = downward force = 10,000N Net Force = 51,800N up
Example 2 • A fully suited diver weighs 200 pounds. This diver displaces a volume of 3.0 cubic feet of seawater. Will the diver float or sink? • weight of equal volume of seawater: 3.0 ft3 x 64 lb/ft3. = 192 lb. Weight of diver = down force = 200 lbs Displaced weight of sea water = up force = 192 lb net force = 8 lbs down • The diver will sink. This diver weighs 8 pounds in the water and is over-weighted. Removal of eight pounds will allow the diver to “hover”.
Buoyancy • Similar to parcel of air in atmosphere • At Equilibrium • Density of Parcel Same as Density of Environment (courtesy F. Remer)
Archimedes Principle • Translation: • objects more dense than water will sink - negatively buoyant ; • objects less dense than water will float - positively buoyant; • objects of the same density will remain at the same level and neither sink nor float - neutrally buoyant.
Buoyancy • Density Difference Results in Net Buoyancy Force B
Buoyancy • Density Difference Results in Net Buoyancy Force B
Buoyancy • Net Buoyancy Force B
Archimedes’ Principle • Water is in hydrostatic equilibrium • ρ = density • g = acceleration of gravity B