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Section 4.6 Text Problem # 9 Solution Manual ACS Page # 165 Solution Problem # 9. Chapter 4 Systems of Linear Equations. Section 4.6. Linear Programming. Chapter 4 Systems of Linear Equations. Section 4.6. Example #1.
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Section 4.6 Text Problem # 9Solution Manual ACSPage # 165Solution Problem # 9
Chapter 4 Systems of Linear Equations Section 4.6 Linear Programming
Chapter 4 Systems of Linear Equations Section 4.6 Example #1
Graph the solution set to the system of inequalities and identify each vertex of the region.
Section 4.6 Text Problem # 11Solution Manual ACSPage # 165Solution Problem # 11
Chapter 4 Systems of Linear Equations Section 4.6 Example #2
Graph the solution set to the system of inequalities and identify each vertex of the region.
Section 4.2 Text Problem # 33Solution Manual ACSPage # 133Solution Problem # 29
Chapter 4 Systems of Linear Equations Section 4.6 Example #3
The publicity director for Mercy Hospital is planning to bolster the hospital’s image by running a TV ad and a radio ad. Due to budgetary and other constraints, the number of times she can run the TV ad, x, and the number of times that she can run the radio ad, y, must be in the region shown in the figure. The function: A = 9000x + 4000y gives the total number of people reached by the ads.
a)Find the total number of people reached by the ads at each vertex of the region. b) What mix of TV and radio ads maximizes the number of people reached?
a) Number of radio ads Number of TV ads A(0,0) = 0 320,000 A(0,80) = 9000(0) + 4000(80) = A(50,0) = 9000(50) + 4000(0) = 450,000 A(30,60) = 9000(30) + 4000(60) = 510,000
Number of radio ads Number of TV ads b) Maximum value at (30, 60). To maximize the audience they should use 30 TV ads and 60 radio ads.