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Solving Literal Equations and Formulas

Solving Literal Equations and Formulas. Lesson 2-5. literal. equation. A _______________ _______________ is an equation that involves two or more variables. Rewriting a Literal Equation:. – 2x + 5y = 12 Solve for y .

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Solving Literal Equations and Formulas

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  1. Solving Literal Equations and Formulas Lesson 2-5

  2. literal equation A _______________ _______________ is an equation that involves two or more variables. Rewriting a Literal Equation: –2x + 5y = 12 Solve for y. _________________________________ Add 2x to each side to “move” the x-term (You are trying to get “y” by itself.) _________________________________ Simplify _________________________________ Divide by 5 _________________________________ Simplify – 2x + 2x + 5y = 12 + 2x 5y = 12 + 2x Note: I work most of my literal equations vertically because often there are no like terms to line up when adding or subtracting.

  3. B. a – 2b = –10 Solve for b. ________________________________ Subtract a from each side. ________________________________ Simplify ________________________________ Divide by –2 ________________________________ Simplify a – 2b – a = – 10 – a – 2b = – 10 – a

  4. Factor each of the following expressions: C. –3x – 9 = ____ (x + 3) D. 2xy + 6y = ____ (x + 3) E. 9x – 18 = ____ (x – 2) F. ax – bx = ___ ( ____ – ____ ) This is like doing the distributive property in reverse – 3 2y 2y x a b

  5. Rewriting a Literal Equation with only (mostly) Variables mx+ 2nx = p Solve for x. ______________________________________ Use the distributive property to factor out the x _______________________________________ Divide both sides by ________. _______________________________________ Simplify x(m + 2n) = p m + 2n

  6. Rewriting Formulas A formula is an equation that states a __________________ among quantities. Formulas are special types of ______________ _____________________ Some formulas you should know are on the table below: relationship literal equations

  7. Josh is planting a rectangular garden. The perimeter of the garden is 120 yd., and the width is 20 yd. What is the length of the garden? Solve the formula for length: Substitute the value of P and w: __________________________ ____________________________ __________________________ ____________________________ __________________________ ____________________________ __________________________ __________________________ P = 2l + 2w P – 2w = 2l + 2w – 2w P – 2w = 2l 40 = l

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