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Engineering Math Project. Boat across the River. Lets start. Supervised By Mr. yahya alskaji. Term 2. 2011 - 2012. Task 1. Students will search the web to find real life examples on working with vectors, e.g. adding forces, projectile, components, vectors in 3D, etc….
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Engineering Math Project Boat across the River Lets start Supervised By Mr. yahyaalskaji Term 2 2011 - 2012
Task 1 Students will search the web to find real life examples on working with vectors, e.g. adding forces, projectile, components, vectors in 3D, etc… Vectors: Mathematics & Physics a quantity having direction as well as magnitude, esp. as determining the position of one point in space relative to another.
Task 2 If the boat is heading due north as it crosses a river with velocity 10 km/h of relative to water, the river has a uniform velocity of 5 km/h due to east. Graph the vectors in the chart below. Then determine the magnitude and direction of the boat’s velocity. 5 km/h to east Velocity of the river 10km/h to north Velocity of the boat The resultant velocity 11.18 km/h and 63.4o above the horizontal
Task 3 The boat is part of delivering company, it can hold 1200 kg and its capacity is 7.20 cubic meter. The service handles two types of boxes: small, which weight is up to 20 kg and no more than 1200 cm2, and large which 25 kg each and 1600 cm3 each. The delivery service charges 10Dhs for each small package, and 15 for each large package. Let : x be the number of small boxes y be the number of big boxes • a. Write an inequality to represent the weight of the packages in kg the boat can hold. • b. Write an inequality to represent the volume in cubic meter of packages the boat can hold.
Task 3 • c. Graph the system of inequality (0,48) (0,0) (60,0) • d. Write a function that represents the amount of money the delivery service will make on each boat hold. f(x,y) = 10 x + 15 y
Task 3 • e. Find the number of each type of the boxes that should be placed on a boat to maximize revenue. ( 0 , 48 ) , ( 0 , 0 ) , ( 60 , 0 ) F (0,48) = 10(0) + 15(48) = 720$ F (0,0) = 10(0) + 15(0) = 0 F (60,0) = 10(60) + 15(0) = 600$ To maximize the revenue they should deliver 0 small package and 48 large package • f. What is the maximum revenue per boat? F (0,48) = 10(0) + 15(48) = 720$ F (0,0) = 10(0) + 15(0) = 0 F (60,0) = 10(60) + 15(0) = 600$ The maximum revenue is 720$
Task 4 =121.24 N Task 5 W= 200 X 6 Sin 30 = 600 J
Thank You For Your Time