260 likes | 378 Views
Unary Not operator !. !true = false !false = true. Example. if (( interMarks > 45) && ( testMarks >= passMarks )) { cout << “ Welcome to Lahore University”; } . Nested if. If (age > 18) { If(height > 5) { : } } Make a flowchart of this nested if structure….
E N D
Unary Not operator ! • !true = false • !false = true
Example if ((interMarks > 45) && (testMarks >= passMarks)) { cout << “ Welcome to Lahore University”; }
Nested if If (age > 18) { If(height > 5) { : } } Make a flowchart of this nested if structure…
Programming Fundamentals Lecture 6
In the last lecture Conditional Construct if if-else
Loop - Repetition structure In our day to day life, most of the things are repeated. Days and nights repeat themselves 30 times a month. Four seasons replace each other every year. We can see similar phenomenon in the practical life. For example, in the payroll system, some procedures are same for all the employees. These are repeatedly applied while dealing with the employees. So repetition is very useful structure in the programming.
Example int sum ; sum = 1+2+3+4+5+……..+10 ; cout << sum ;
While While means, 'do it until the condition is true'.
while ( Logical Expression ) { statements; : }
Example int sum ; sum = 0 ;
Example int sum = 0; ( Optional )
Example int sum , number ; sum = 0 ; number = 1 ; while ( number <= 1000 ) { sum = sum + number ; number = number + 1 ; } cout << “ The sum of the first 1000 integer starting from 1 is ” << sum ;
Example int sum, number , UpperLimit ; sum = 0 ; number = 1 ; cout << “ Please enter the upper limit for which you want the sum ” ; cin >> UpperLimi t; while (number <= UpperLimit) { sum = sum + number ; number = number +1 ; } cout << “ The sum of the first ” << UpperLimit << “ integer is ” << sum ;
if ( number % 2 == 0 ) { sum = sum + number ; number = number + 1 ; }
Example sum = 0; number = 1; cout << “ Please enter the upper limit for which you want the sum ”; cin >> UpperLimit; while (number <= UpperLimit) { if (number % 2 == 0) { sum = sum + number; } number = number + 1; } cout << “ The sum of all even integer between 1 and ” << UpperLimit << “ is” << sum;
Infinite Loop: • Consider the condition in the whilestructure that is (number <= upperLimit) and in • the whileblock the value of numberis changing (number = number + 1) to ensure that • the condition is tested again next time. If it is true, the whileblock is executed and so • on. So in the whileblock statements, the variable used in condition must change its • value so that we have some definite number of repetitions. What will happen if we do • not write the statement number = number + 1;in our program? The value of number • will not change, so the condition in the whileloop will be true always and the loop • will be executed forever. Such loops in which the condition is always true are known • as infinite loops as there are infinite repetitions in it.
#include<iostream.h> void main() { inta,b; cout<<" Input the first printing value :" ; cin>>a; cout<<endl; cout<<"Input the last printing value :" ; cin>>b; cout<<endl; while(a<=b) { cout<<" The Print out value is :"<<a; cout<<endl; a++; } }
Innovations • Write the same program but now with fix values
#include<iostream.h> void main() { inta; a=1; while(a<=10) { cout<<a<<endl; a++; } cout<<endl; }
Innovations • Write the same program but now take values from user
Factorial Definition n! = n*(n-1)*(n-2)*(n-3)…………*3*2*1
Property of While Statement • In the above example, if the user enters 0, as the value for upper limit. In the while condition we test (number <= upperLimit) i.e. number is less than or equal to upperLimit( 0 ), this test return false. The control of the program will go to the next statement after the while block. The statements in while structure will not be executed even for a single time. So the property of while loop is that it may execute zero or more time.