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Price Is Right. Events example and instructions. Do Now Prob and Stat. Take out your Price is Right Game. Take 2.
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Price Is Right Events example and instructions
Do Now Prob and Stat • Take out your Price is Right Game
Take 2 The contestant is shown four prizes and a total which represents the price of two prizes added together. The contestant has two chances to choose the two prizes whose prices match the total given. A correct choice wins all four prizes.
Permutations and Combinations • In “Take 2”, the player is shown 4 prizes and he or she by selecting the 2 prizes that add up to the total given. • Combinations can be used to determine the total number of possible outcomes for a players first selection • 4C2 = 6 outcomes • This was also shown using a tree diagram
Take 2 • http://www.youtube.com/watch?v=rp_7iOr-tyA
Events • Tree diagram 4 prizes are shown A B C D B Let E = The event that a correct choice is made on the first selection C D C D
Events • Tree diagram 4 prizes are shown A B C D B Let E = The event that a correct choice is made on the first selection P(E) = C D C D
Events • Tree diagram 4 prizes are shown A B C D B Let E₂ = The event that a correct choice is made on the second selection This means that: C D C D
Events • Tree diagram 4 prizes are shown A B C D B Let E₂ = The event that a correct choice is made on the second selection P(E₂) = 1/5 C D C D
Instructions • Make a tree diagram • Assign events that correspond to all possible outcomes for your winning your game • Determine the probability of each event
Take 2 The contestant is shown four prizes and a total which represents the price of two prizes added together. The contestant has two chances to choose the two prizes whose prices match the total given. A correct choice wins all four prizes.
Events and Probability • Let E = the event that a player makes a correct choice on the first try • P(E) = 1/6 • Let E₂= the event that a player makes a correct choice on the second try, given incorrect on the first • P(E ₂)= 1/5
Mutually Exclusive and Independence • Since P(E₂) P(E₂|E ) the events are dependent • Since P( E and E₂ ) = O The events are mutually exclusive
Probability of Winning • P(winning) = P(E or E ₂) = 1/6 + 1/5 = 11/30 • Probability of winning this game involves winning on the first try or winning on the second. I can use the addition rule for mutually exclusive events, since E and E₂ are mutually exclusive