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On the degree of symmetric functions on the Boolean cube. Joint work with Amir Shpilka. The basic question of complexity. The basic question of complexity. How complex is it (how hard it is to compute f?). The basic question of complexity. How complex is it (how hard it is to compute f?)
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On the degree of symmetric functions on the Boolean cube Joint work with Amir Shpilka
The basic question of complexity How complex is it (how hard it is to compute f?)
The basic question of complexity How complex is it (how hard it is to compute f?) That depends on the computational model at hand. e.g. Turing machines, Circuits, Decision trees, etc…
Polynomials as computers How complex is it (how hard it is to compute f?) That depends on the computational model at hand. e.g. Turing machines, Circuits, Decision trees, etc… Our model of computation – Polynomials.
Polynomials as computers Our model of computation – Polynomials.
Polynomials as computers Our model of computation – Polynomials.
Tight lower bound Nisan and Szegedy (94) proved assuming f depend on all n variables.
Tight lower bound Nisan and Szegedy (94) proved assuming f depend on all n variables. Can we get stronger lower bounds on more restricted natural classes of functions?
Symmetric Boolean functions Von zurGathen and Roche (97) proved assuming f is non-constant.
Symmetric Boolean functions c .. . 2 1 0 0 1 2 3 4 5 6 . . . n
Symmetric Boolean functions c .. . 2 1 0 0 1 2 3 4 5 6 . . . n
Symmetric Boolean functions What can be said about ? c .. . 2 1 0 0 1 2 3 4 5 6 . . . n
Symmetric functions What can be said about ? For c=1 we got For c=n the function has degree 1.
Symmetric functions What can be said about ? For c=1 we got For c=n the function has degree 1. How does the degree behaves?
Symmetric functions Von zurGathen and Roche noted that
Symmetric functions Von zurGathen and Roche noted that In particular, even for this observation doesn’t exclude the existence of a parabola interpolating on some function.
Relative degree Define
Relative degree Define is monotone decreasing in c.
Relative degree Define is monotone decreasing in c. has a crazybehavior in n.
Relative degree Define is monotone decreasing in c. has a crazybehavior in n.
6 stages of first-time research Stage 1
6 stages of first-time research Stage 2
6 stages of first-time research Stage 3
6 stages of first-time research Stage 4
6 stages of first-time research Stage 5
6 stages of first-time research Stage 6
6 stages of first-time research Stage 1…
Our main result Main theorem This proves a threshold behavior at c=n.
Our main result Main theorem This proves a threshold behavior at c=n. Yet another theorem
Proof strategy – reducing c Lemma 1. For any n there exist a prime p such that and
Proof strategy – reducing c Lemma 1. For any n there exist a prime p such that and Together with the trivial bound , we already get a threshold behavior
Proof strategy – reducing n Lemma 2. For every c,m,n such that , it holds that Dream version
Proof strategy – reducing n Lemma 2. For every c,m,n such that , it holds that Dream version
Proof strategy – reducing n Lemma 2. For every c,m,n such that , it holds that Dream version
Proof strategy – reducing n Lemma 2. For every c,m,n such that , it holds that
Proof of the main theorem A computer search found that . By Lemma 2 By Lemma 1
Periodicity and degree Low degree Strong periodical structure Dream version
Periodicity and degree Low degree Strong periodical structure Strong periodical structure High degree Dream version
Periodicity and degree Low degree Strong periodical structure Strong periodical structure High degree Hence no function has “to low” degree. Dream version
Periodicity and degree Low degree Strong periodical structure Strong periodical structure High degree Not the same sense of periodical structure…
Low degree implies strong periodical structure Lemma 3. Let with . Let be a prime number. Then for all such that it holds that c .. 1 0 0 1 2 3 . . . d . . . p n
Low degree implies strong periodical structure Lemma 3. Let with . Let be a prime number. Then for all such that it holds that c .. 1 0 0 1 2 3 . . . d . . . pq n
Low degree implies strong periodical structure Lemma 3. Let with . Let be a prime number. Then for all such that it holds that c .. 1 0 0 1 2 3 . . . d . . . pq r n
Strong periodical structure implies high degree Definition. Let and define
Strong periodical structure implies high degree Definition. Let and define
Strong periodical structure implies high degree Definition. Let and define Lemma 4. Let . Then for all If then If then or