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Statics – deals with the action of forces on bodies at rest. Net force acting on the body is zero

Engineering Mechanics – deals with the state of a body at rest or motion of a body caused by the action of forces. Statics – deals with the action of forces on bodies at rest. Net force acting on the body is zero.

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Statics – deals with the action of forces on bodies at rest. Net force acting on the body is zero

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  1. Engineering Mechanics – deals with the state of a body at rest or motion of a body caused by the action of forces. Statics – deals with the action of forces on bodies at rest. Net force acting on the body is zero Dynamics – deals with the motion of bodies under the action of forces. Net force acting on a body is not zero. • Kinematics– study of motion without reference to the forces which cause the motion. Deals with position, velocity, and acceleration in terms of time • Kinetics– relates the action of forces on bodies to their resulting motions Mechanical Engineering Department

  2. Particle A body , not necessarily small, where it’s motion can be characterized without considering its size and orientation. Rotation of the body about its own axis is neglected. Rigid body The body is called a rigid body If its rotation about its own axis cannot be neglected. Mechanical Engineering Department

  3. Problem Solving Technique Identify all given data (known parameters) Identify the goal (unknown parameters) Draw diagrams needed to solve the problem: Free Body Diagram (FBD), Motion Diagram (inertial Response Diagram), Geometry Diagram Identify the dynamics principles applied to the problem Clearly state all assumptions Mechanical Engineering Department

  4. Problem Solving Technique Use your technical judgment (common sense) to determine if the answer is reasonable Report the answer with the same accuracy as the given data Careless solutions that cannot be read easily are of little or no value. Mechanical Engineering Department

  5. Example Consider the Bat-Sled as shown. At time zero its rocket engine is fired, producing a thrust of T = 43,000 N. The mass of the sled is m = 1600 kg and the coefficient of friction between the sled and snow is 0.2. Determine the sled’s acceleration. Known parameters: Total mass (m), thrust (T) and coefficient of friction () Goal (unknown): Acceleration of the sled, a Draw diagrams: FBD = MD (IRD) FBD MD Mechanical Engineering Department

  6. Dynamics principles (formulate equations): Summation of forces in the x direction Summation of forces in the y direction Assumptions For the sled to move, the thrust has to overcome the friction between the snow and the sled. We have to check this assumption later. ? T > F =  N There is no motion of the Bat-Sled in the vertical direction. F =  N The Bat-Sled will not flip over. Solve Acceleration = 2.54 g Check Check assumption, is the answer reasonable? Mechanical Engineering Department

  7. Some Reference Values Acceleration, SI system (English system) Fast car 3 m/s2 (118 in/ s2) Hard braking car 7 m/s2(275 in/ s2) Earth gravity at sea level 9.81 m/s2 (32.2 ft/ s2) Humans blackout 40 m/s2(4 g-force) • Belly flopping in water from 10 m diving board, causing broken bones 100 m/s2 (10 g-force) Head-on car collision occupant acceleration 10,000 m/s2(2730 ft/ s2) Bullet fired from a rifle 60,000 m/s2 (16,400 ft/ s2) Centrifugal acceleration of light trapped in a black hole 2 x 1013 m/s2 (550 x 1013 ft/s2) Mechanical Engineering Department.

  8. Some Reference Values Force, SI system (English system) Attraction between electron and proton in hydrogen 0.08 μ N (.018 μ lb.) Weight of a piece of paper 0.04 N (.14 ounce) Weight of a small apple 1 N (.22 lb.) Finger force for appliance 7 N (1.6 lb.) Weight of bag of potatoes 100 N (22.5 lb.) Weight of two small people 1.5 kN (337 lb.) Thrust of Boeing 747 1 MN (224, 820 lb.) Space shuttle thrust 0.2 GN (45 million lbs.) Mechanical Engineering Department.

  9. Geometry diagram FBD = MD (IRD) Mechanical Engineering Department

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