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STOICHIOMETRY PRACTICE PROBLEMS. Mole-Mole Problem. Equation for the following problem: 2 Al 2 O 3 => 4 Al + 3 O 2. How many moles of Al could be produced from 13.0 moles of Al2O3?. 2 mol Al 2 O 3 = 4molAl => 2X = 4 x 13
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Mole-Mole Problem Equation for the following problem: 2 Al2O3 => 4 Al + 3 O2 How many moles of Al could be produced from 13.0 moles of Al2O3? 2 mol Al2O3 = 4molAl => 2X = 4 x 13 13 mol Al2O3 X 2X = 52 X = 26 mol Al 2 2 or 13mol Al2O3 x 4mol Al = 26 mol Al 2 mol Al2O3
Mole- Mass Problem Equation for the following problem: 2 Al2O3 => 4 Al + 3 O2 How many grams of O2 would be produced from 22 moles of Al2O3? 22 Al2O3 * 3 mol O2 * 32.00g O2 2 mol Al2O3 1 mole O2 = (22mol X 3 mol X 32g) / 2 mol = 1056 = 1.06 E 3g O2
Mass-Mole Problem Equation for the following problem: 2 Al2O3 => 4 Al + 3 O2 How many moles of Al would be produced from 890 grams of Al2O3? 890g Al2O3 * 1 mol Al2O3 * 4 mol Al = 17 mol Al 102.0g Al2O3 2 mol Al2O3
Mass- Mass Problem Equation for the following problem: 2 Al2O3 => 4 Al + 3 O2 How many grams of O2 would be produced from 641 grams of Al2O3? 641g Al2O3 x 1 mol Al x 3mol O2 x 32g O2 27g Al 2mol Al2O3 1 molO2 = 301.65 = 302g O2