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Newton’s 2 nd Law Lab 4 Only 8 more to go!!

Newton’s 2 nd Law Lab 4 Only 8 more to go!!. Newton’s 2 nd Law says that the acceleration of an object is directly proportional to the total force applied and inversely proportional to the object’s mass. Mathematically: . We usually write Neton’s 2 nd law:.

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Newton’s 2 nd Law Lab 4 Only 8 more to go!!

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  1. Newton’s 2nd Law Lab 4 Only 8 more to go!! Newton’s 2nd Law says that the acceleration of an object is directly proportional to the total force applied and inversely proportional to the object’s mass. Mathematically: We usually write Neton’s 2nd law: Consider this situation, what is the acceleration of the box? +y F2=300N F1=200N m= 10 kg +x

  2. Consider this situation: 1st is to draw a FBD for each mass + + + m1: Tension, T m2: Tension, T + + m1 m2 Weight, m1g Weight, m2g 2nd step is to write down Newton’s 2nd law for each mass is to draw a FBD for each mass: m1: m1g – T = m1a Now we have a situation where we have m2: -m2g + T = m2a 2 equations and 2 unknowns. By adding +: m1g – m2g = m1a +m2a these equations we can solve for, a Substituting back into one of the other equation we can solve for the tension

  3. Consider the situation when m1= 10 kg and m2 = 8 kg What if m1 = m2? Notice that a will equal 0, and the tension becomes equal to mg F = 400 N Let’s look at this problem: If the object starts from rest, how fast is it moving after 10 seconds? 20o 10 kg We need to find the object’s acceleration using Newton’s 2nd law!

  4. Now plug this acceleration into v = v0 + at V = 0 + (37.6 m/s2) (10 s) = 376 m/s

  5. FN Here is what we are doing in lab today: T mc mc T mcg mw mw Write down the equations from Newton’s 2nd law: Weight: mwg – T = mwa Cart: T = mca Add the equations together mwg = (mw + mc) a SOLVE FOR a : mwg

  6. + INCLINE PLANE FN + T + mc mw height  mcg mwg  We use the same procedure, 1st FBD, 2nd we write newton’s second law: Weight: mwg – T = mwa Cart: T-mcsin = mca Add these guys: mwg-mcsin = mwa + mca SOLVE FOR a:

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