E N D
1. Eric The Sheep Heath, Rainer, Nathan and Tom
2. How We Figured It Out First off, we made a table of the answers up to 20, figuring the answers out by drawing them out.
We saw a pattern emerge, for every three sheep in front of Eric, the number would increase
3. FOR EVERY 1 SHEEP SHORN, ERIC WILL JUMP 2 SHEEP
5. Formula for 1 sheerer X
3 + 1
(except if the value of x is a multiple of 3, ie. 3, 6, 9, 12)
You must only take the integer and leave out the decimal numbers.
Example. 5/3+1= 2
Example. 12/3= 4
6. A second formula A second formula we found to work was: if the number of sheep in front of Eric is a multiple of 3, simply divide by 3. If not, round the number up to the closet multiple of 3, ie. Round 19 up to 21 and divide by 3 to find 7, the answer.
8. Questions 2. Yes, You can predict it using the formula. All you have to do is round up to the next multiple of 3 and then divide by 3.
9. 3. If Eric was to jump 4 round up to to the next multiple of 4 and divide by 4. Same with method used with 5, just sub in 5 instead of 4
10. FOR EVERY 3 SHEEP SHORN, ERIC WILL JUMP 2 SHEEP
12. Pattern for 3 shearers A pattern emerged, No. shorn before Eric, goes up by 1 , up by 1 again, then up by 1 and stay the same for the next 3, then repeats I.e. 1,2,3,3,3,4,5,6,6,6
The number at the end of the three same numbers created a ratio with the No. in front of Eric, of 5:3 I.e. 20:12, 15:9, 10:6
To figure out, round the number in front of Eric up to the next multiple of 5, then use the pattern to figure it out and count back
13. Tried method 472 sheep in front of Eric, round up to 475, sub into ratio 5:3
475:285, divide down= 5:3
Count 285 back 3 places (475-472=3) answer is 282
14. Thank You