1 / 5

9.9 (Day 2) Systems of Linear Equations in Three Variables – Word Problems

9.9 (Day 2) Systems of Linear Equations in Three Variables – Word Problems. Example .

ariane
Download Presentation

9.9 (Day 2) Systems of Linear Equations in Three Variables – Word Problems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 9.9 (Day 2) Systems of Linear Equations in Three Variables – Word Problems

  2. Example Alex has nickels, dimes, and quarters worth $3.05. The number of dimes is six less than the sum of the number of nickels and quarters. If there are 24 coins in all, how many of each type of coin does Alex have? • Identify variables: n = # of nickels d = # of dimes q = # of quarters  worth 5¢ each  worth 10¢ each  worth 25¢ each

  3. Example Alex has nickels, dimes, and quarters worth $3.05. The number of dimes is six less than the sum of the number of nickels and quarters. If there are 24 coins in all, how many of each type of coin does Alex have? • Write the equations: 5n + 10d + 25q = 305 d = n + q – 6 n + d + q = 24 • rewrite in order • n – d + q = 6

  4. Example • Solve: 5n + 10d + 25q = 305 n – d + q = 6 n + d + q = 24 ( )(10) 2n + 2q = 30 n + q = 15 ( )(–15) 5n + 10d + 25q = 305 10n – 10d + 10q = 60 n + 7 = 15 n = 8 15n + 35q = 365 8 + d + 7 = 24 –15n – 15q = –225 d = 9 20q = 140 8 nickels, 9 dimes, 7 quarters q = 7

  5. Homework #5 Pg. 448 13, 15 Word Problems 1 – 3 all

More Related