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Chapter Fifteen. Thermodynamics. 1 st Law of Thermodynamics. The Change in a system’s internal energy is related to heat and work. Internal Energy :. 1 st Law of Thermodynamics. The Change in a system’s internal energy is related to heat and work. Conservation of energy. +Q -Q +W
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Chapter Fifteen Thermodynamics
1st Law of Thermodynamics The Change in a system’s internal energy is related to heat and work Internal Energy:
1st Law of Thermodynamics The Change in a system’s internal energy is related to heat and work Conservation of energy +Q -Q +W -W System GAINS heat System LOSES heat System DOES work –Loses energy Surrounding DOES work on the system
Quasi-static Thermal Processes -Isobaric -Isovolumetric -Isothermal -Adiabatic Meaning that the processes take place slow enough that system has UNIFORM temperatures and pressures
Isobaric Processes occurring at a CONSTANT PRESSURE -Expansion Vs. -Compression System does work Vs. Surrounding does work +Work Vs. -Work
Isobaric Processes occurring at a CONSTANT PRESSURE
Isovolumetric Processes that occur at a constant VOLUME.
Isothermal Processes occurring at a constant TEMPERATURE • Internal energy remains constant
Isothermal Processes occurring at a constant TEMPERATURE Heat transfers energy Work transfers energy
Adiabatic Processes occurring with NO TRANSFER of heat
Adiabatic Processes occurring with NO TRANSFER of heat
Example Problem The largest glass-blown bottle is 2 m tall. The pressure used to expand the bottle is 5.1 kPa. If 3600 J of work is done in expanding the bottle, from an initial volume of 0.0 m3, what is the final volume? V=0.71 m3
2nd Law of Thermodynamics: Heat only spontaneously flows from a substance of higher temperature to a substance of lower temperature
Any device that uses heat to perform work Heat Engines: Heat supplied from the relatively hot reservoir Part of the heat is used to do work Remainderis relatively cold. Goes into the cold reservoir
Efficiency: In a heat engine, some energy is lost
Carnot’s IDEAL Efficiency: Substance of machine is ignored This allows for a prediction of ideal efficiency TEMPERATURE IN KELVIN!!! TEMPERATURE IN KELVIN
Example problem If a gasoline engine has an efficiency of 30 % and loses 920 J of heat to the environment, how much work is done by the engine? W=394 J
2nd Law of Thermodynamics: Heat only spontaneously flows from a substance of higher temperature to a substance of lower temperature -No heat engine can ever be 100% efficient. So heat energy is lost to the environment
Refrigeration: Evaporation Coils Refrigerant boils at 20° F In the Evaporation Coils: -Refrigerant absorbs heat and vaporizes No work is done.
Refrigeration: Compressor In the Compressor: -Gas is compressed -Work is done -Pressure and internal internal energy are increased
Refrigeration: Condenser Coil In the Condenser Coil: -Heat transfers out of refrigerant -Refrigerant cools and condenses -No Work
Refrigeration: Expansion Valve In the Expansion Valve: -Liquid expands -Work is done -Internal energy is decreased -No heat is transferred
Refrigeration: Cyclic Process: Energy is transferred (through heat and work) but there is no NET change in internal energy
Entropy: • Measure of a system’s disorder • Systems left alone move toward a more disordered state • Disordered states tend to remain disordered • Greater disorder leads to less energy available for work. Entropy can be decreased by doing work
2nd Law of Thermodynamics: Heat only spontaneously flows from a substance of higher temperature to a substance of lower temperature -No heat engine can ever be 100% efficient. So heat energy is lost to the environment The entropy of the universe increases in all processes -A system’s entropy can decrease only if offset by an increase elsewhere